I'm designing feedback loop compensator for inverter. here i have H bridge, output transformer and output capacitor. it is just like dc dc converter for inverter so i needed to know How to calculate series inductance of a transformer
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\$\begingroup\$ What is your numerical or technical starting point? \$\endgroup\$– Andy akaCommented Mar 16, 2016 at 14:46
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\$\begingroup\$ i did not get you Mr. andy \$\endgroup\$– krsCommented Mar 17, 2016 at 4:01
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\$\begingroup\$ What inductance do you need. What current is it rated at. These are numbers. \$\endgroup\$– Andy akaCommented Mar 17, 2016 at 8:01
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\$\begingroup\$ transformer is 1:33, input is PWM unipolar pulse, current rating is 80A for 1kVA transformer, input is about 7.5V and output is 230V(aprox.) \$\endgroup\$– krsCommented Mar 17, 2016 at 9:14
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\$\begingroup\$ Andy aka can you please reply me \$\endgroup\$– krsCommented Mar 18, 2016 at 10:09
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1 Answer
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Steps
- What you have to know is the transformer rating.
- Let's say the current rating is 10A for example.
- short circuit the secondary but measure the current through the short.
- You will need a phase angle meter such as an Arbiter 928A
- Energize the primary with a voltage source being careful not to exceed the 10 amps on the secondary
- Put the voltage channel A of the arbiter across the voltage element and measure the current using channel B of the arbiter. The arbiter will show the current with a positive lag angle theta by default. Say we get 45 degrees. This means that the voltage on channel A is 0 degrees and the current on channel B is 360-45=315 degrees. Say it took 10 volts to do this and the current in the primary is 2 amps. Z = 10 < 0 degrees / 2 < -45 degrees = 5 ohms < 45 degrees.
Theory
Z = V/I, its the LAW!!
Where I = the current through the primary. Where V = the voltage across the primary.
simulate this circuit – Schematic created using CircuitLab
