# Motherboard RGB diode control and resistance?

I've recently acquired a new motherboard for my PC which features RGB strip control. That's well and good but I have particular need to control a single RGB diode with that same header.

The issue I'm facing now is that I'm not sure what form of resistors I need for my single RGB diode. I know I will need 3 of them. I plan to use a female to male connector then into a ribbon cable to the diode.

My motherboard is an ASUS HERO Maximus Alpha: LINK HERE

This is noted on the Asus page: *The Aura RGB-strip header supports standard 5050 RGB LED strips with a maximum power rating of 2A (12V)

Here is the data sheet for said diode: How do I calculate the resistors required to control this LED?

The datasheet gives you the forward voltage of each LED at 20 mA and you have a 12 V supply. Your series resistor, therefore has to drop $12 - V_f$ volts at 20 mA. From Ohm's Law we can calculate the series resistance for each LED as
$$R = \frac {V}{I} = \frac {12 - V_f}{0.02}$$
@Passerby is right that we should check the power dissipation in the resistors too. For example, your red LED calculation (in comments) gave a value of 500 Ω for a $V_f$ of 2.0 V:
$$P = \frac {V^2}{R} = \frac {(12-2)^2}{500} = \frac {10^2}{500} = \frac {100}{500} = 0.2~W$$