# Finding R for max power deliverable to R and determining the max power

This relates to max power transfer. Here's my circuit: simulate this circuit – Schematic created using CircuitLab

My goal is to try and find the value of R for the maximum power that can be delivered to it. Then I'll calculate that power as well. I have tried drawing the circuit with an a port on the left of the R resistor and a b port on the right of the R resistor and then trying to calculate Rth by shorting the independent voltage sources, but each time I do that and apply KCL or KVL I get equations that equal zero or not enough equations to solve for all the unknowns.

That's just Rth, I do not even know where to get started for calculating Vth for this circuit. My best guess is that I will ignore the R or load resistor and then apply nodal analysis or some other techniques but I'm not sure which one to use.

I know these equations: $$V_{oc}=V_{th}\;\;\;\;\;\;I_N=I_{sc}\;\;\;\;\;\;R_N=R_{th}={V_{oc}\over I_{sc}}\;\;\;\;\;\;R_L=R_{th}\;\;\;\;\;\;p_{max}={V_{th}^2 \over {4R_{th}}}\;\;\;\;\;\;When\;\;\;R_L \ne R_{th}\;\;\;p=i^2R_L=({V_{th}\over{R_{th}+R_L}})^2R_L$$ I know those equations but just do not know how to get them correctly.

Sorry I can't show work or explain it more, this is as far as I can get right now. Any help would be very appreciated. Thank you!

Right now I'm most familiar with superposition, Thevenin, Norton, Nodal, Mesh, and Ohm's law.

EDIT: in case anyone is still reading this, I'm still stuck and every time I try to solve for Voc or Isc I get a system of equations that can't be solved.

• I'd rather try to get Thevenin equivalent through short circuit current and open circuit voltage at R port.. you'll get two simple to solve circuits. It is always good idea to cut the problems into smaller chunks, brute force approach is for computers instead. – carloc Oct 5 '18 at 8:53
• I don't see how the current dependent voltage source or the $1\:\Omega$ resistor means anything to the answer. You could just drop those out of the circuit and ground that now-loose end of the remaining voltage dependent current source and still have the same problem to solve. (I suspect you didn't transcribe the circuit well. Perhaps something isn't right?) – jonk Oct 5 '18 at 10:04
• Nope, this is the circuit exactly. – JustHeavy Oct 5 '18 at 18:11
• @JustHeavy I'm trying to get you to see something here that makes this circuit somewhat unique (in a mathematical sense.) Given the other comments here, I am not sure others who've written yet "see" the issue. They seem to imagine that if you follow a basic process the end of that path with give you something reasonable. Actually, this is an interesting question now that I look more closely. – jonk Oct 5 '18 at 20:44
• Thanks for your input, but from what I have learned so far I can't see how I could just 'lose' the dependent source. I'm starting to think I can't find the value R. I have put too many hours into this problem now. – JustHeavy Oct 5 '18 at 20:52

Use Thevenin, with $$\\small R\$$ as the load. Determine $$\\small R_{TH}\$$ (turn all sources off); then maximum power transfer will be when $$\\small R=R_{TH}\$$. No need to determine $$\\small V_{TH}\$$ or $$\\small I_{SC}\$$.
• @carloc $\small R_{TH}$ is simply 2||4 ohms. The question appears to be to find R, and '... then I'll calculate the power as well...' looks like an afterthought. – Chu Oct 5 '18 at 10:37