I recently purchased a small 1 inch OLED screen. In the datasheet, it shows the max power requirements as:

Operation: 3.5v
Logic: 2.6v
IO: 3.5v
Display: 13.5v

I figure I can directly connect the operation and IO pins to the 3.3v power. I guess for the logic pin, I'd use a voltage divider circuit? What about the display? Since it's a small little screen, I don't expect the current to be much of an issue, but how do I boost the voltage from 3.3v to 13v?

Since I'm new, I would normally use a pre-made breakout board, but in this case I'd rather learn how to do it instead.

Edit: The driver is a SSD1351. Here is a link to the datasheet: SSD1351

Edit 2: The datasheet I have for the display is marked as 'Confidential' and doesn't appear available online. I got it sent in email from the manufacturer. So I don't have a link, but I found the current information for the display:

30% of display: 13.3 typical, 17.0 max mA
60% of display: 23.2 typical, 29.0 max mA
100% of display: 33.4 typical, 42.0 max mA

  • \$\begingroup\$ Do you have any reference, or photo of the module? \$\endgroup\$
    – TEMLIB
    Nov 18 '18 at 1:41
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    \$\begingroup\$ You need to specify the maximum current requirement at 13.5V. Chances are good that the logic and I/O will operate from your 3.3V and you just need a 13.5V source for the display. Please link datasheet for the display. \$\endgroup\$ Nov 18 '18 at 3:02
  • \$\begingroup\$ if 13.5 is absolute maximum, changes are good that it will opwerate from 12V, still you'll need a way to boost 3.3 up to 12V for that more details would be good. \$\endgroup\$
    – Jasen
    Nov 18 '18 at 5:13
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    \$\begingroup\$ It's set by a resistor. You need the datasheet for the display as well as the driver. \$\endgroup\$ Nov 19 '18 at 2:40
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    \$\begingroup\$ where do you see 2.6V ? \$\endgroup\$
    – vlk
    Nov 20 '18 at 8:21

Driving OLED displays is easy, but you need to provide two voltages:

  • supply for the digital part of the display is 3.3V from your logic
  • supply for the display drivers is 10V - 18V from any step-up driver (higher voltage means higher brightness and also higher current)

For inspiration of the supply, here is breakout with your display display and also schematic.

  • \$\begingroup\$ Yes, that's it. It looks like the FAN5331 IC does the work. The datasheet has the same circuit in that schematic. Thanks for that! \$\endgroup\$
    – Jason
    Nov 22 '18 at 1:46

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