I need to wire this switch, but I have no idea how. I thought I was buying a normal 3P rocker switch :)
The power source is 12v battery and the load is LED flashlight.
0
Add a comment
|
3 Answers
\$\begingroup\$
\$\endgroup\$
It looks like you can control the LED of this switch separately from the actual switching. If you apply +/- on the "3" contacts, then it will light up the LED on the switch. Then "1"/"2" are the contacts for the switch, simply giving you an open/close.
Unfortunately, it doesn't look like it is what you wanted if you were looking for a 3 position switch. It can be hard buying switches without fiddling with them first to make sure it's what you want.
\$\begingroup\$
\$\endgroup\$
2
I thought I was buying a normal 3P rocker switch :)
simulate this circuit – Schematic created using CircuitLab
Figure 1. (a) A 3P (3-pole) switch would have three independent contacts. (b) A 3P2T (3-pole, double-throw) switch would have three changeover contacts. (c) What you've got and how to wire it.
You've purchased a 1PST (one-pole, single-throw) switch with built-in isolated indicator.
answered Jun 13, 2020 at 15:25
-
1\$\begingroup\$ Don't forget to add a current limiting resistor (\$\approx 1k\Omega \$) in series with the LED. Otherwise the LED will die a sudden death. \$\endgroup\$– HufiJun 13, 2020 at 20:49
-
\$\begingroup\$ Yes, I assumed it was a 12 V indicator but there's nothing in the datasheet to support that. I've added the resistor. \$\endgroup\$ Jun 13, 2020 at 20:53
\$\begingroup\$
\$\endgroup\$
0
It's an SPST rocker switch with a 1.85V 10mA LED as the status indicator.
The switch terminals are 1 & 2 and the indicator terminals 3+ & 3-.
The value of the LED voltage dropping resistor R would depend on the supply voltage.
Here are the cut-out details for mounting the switch.
