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I am trying to fix my robotic sweeper, and I saw this highly suspect capacitor on the PCB, I presume it is gone and needs to be replaced. However I dont see any rating over this unit, so I am not clear on how I can replace it.. Is it something that isnt exposed? Or is it directly tied to the package size?

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enter image description here

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  • \$\begingroup\$ The capacitor just looks like it's dusty. The gunk might be leakage from the nearby electrolytic too. But the picture is so poor it is hard to tell. Also the chip U14 looks like it's cracked and half missing, but again, the picture is so poor it is hard to tell. \$\endgroup\$
    – Justme
    Commented Sep 3, 2020 at 16:43

2 Answers 2

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The short answer is: if it's dead, no way to tell. It's 0402 seems like, and if you can somehow determine its function, it would help you to put a fitting component. But usually you can just kick one cap off and everything will still work (if it doesn't AC couple something).

If it looks like a filtering or a bypass cap (one side is on the ground), a 0.1uF-2.2uF will do fine there. But yeah, if it's a bypass/filtering, things will very likely work without it too. It's best to have caps of different order of magnitudes around, but 0402 don't really get larger than 10uF from my experience. Common bypass is 0.1uF, if it's voltage converter output, put 2.2uF. Of course this differs from situation to situation, but these values will be okay-ish for most common scenarios.

If it's an AC coupling cap, try some small nanofarads like 47nF.

All you can do is indeed try stuff and observe. Again, my bet is everything will work fine even without it.

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  • \$\begingroup\$ Thanks, will remove it and try. Will update here soon \$\endgroup\$
    – Karthik T
    Commented Sep 3, 2020 at 14:16
  • \$\begingroup\$ Removing it didnt help, but I noticed a R100 resistor nearby measuring nearly 100 ohms, gonna try to replace that and try again. \$\endgroup\$
    – Karthik T
    Commented Sep 6, 2020 at 10:43
  • \$\begingroup\$ Thanks for your help, will mark as answer, as it does answer the specific question I asked. \$\endgroup\$
    – Karthik T
    Commented Sep 6, 2020 at 10:44
  • \$\begingroup\$ @ilya electronics.stackexchange.com/users/253935/ilya When you say remove it, do you mean take it off the board and leave the circuit open? Or do you mean take it out and solder a joint between where it was on the PCB? I'm a newbie. I have damaged a capacitor off a IT76630M stepdown DC/DC converter and wondered if I can get away without it. Thanks. \$\endgroup\$
    – Zymotik
    Commented Nov 1 at 12:13
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    \$\begingroup\$ @Zymotik a good capacitor means no connection between terminals, there is a non-conductive gap between them (it won't beep through with a multimeter). Which is why you never replace capacitor with joined pads. Often, if a cap is dead (and therefore conducts while it shouldn't), the solution is to simply remove the cap. If it's not a critical cap like the one and only cap of a voltage regulator output, then your circuit will probably work even without it (or you can replace it of course, that's up to your judgement), \$\endgroup\$
    – Ilya
    Commented Nov 4 at 11:13
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Assuming you mean the ceramic capacitor in that picture, there is no way to know the exact capacitance without measuring it, looking at documentation or inferring from the circuit.

If the capacitor failed as a short, you can often remove the shorted capacitor and not replace it. The local circuit function may be compromised but at least the short circuit will be gone.

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  • \$\begingroup\$ Thanks, will remove it and try. Will update here soon \$\endgroup\$
    – Karthik T
    Commented Sep 3, 2020 at 14:16
  • \$\begingroup\$ Looking at documentation (datasheet) accordin the nearest chip (or find what the chip connected to the capacitor) using typical circuit for it. \$\endgroup\$
    – nick_n_a
    Commented Sep 3, 2020 at 14:45
  • \$\begingroup\$ Removing it didnt help, but I noticed a R100 resistor nearby measuring nearly 100 ohms, gonna try to replace that and try again. \$\endgroup\$
    – Karthik T
    Commented Sep 6, 2020 at 10:43

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