I'm trying to measure the DC resistance of an inductor I made out of AWG 11 wire.
From my calculations its impedance should be around 0.0012 ohm, and the ohmmeter measured precisely 0.0012 ohm.
But that at ambient temperature (which was 18ºC). But I had to measure its impedance at different temperatures too.
Then I tried heating the inductor with an hot air gun from a distance, at the lowest power. It heated to mere 30 ºC and stabilized at that temperature, but the resistance went up to 0.0041 ohm. That sure was impossible, it's too much of an increase due to such a small heating.
When that happened it occurred to me it should be some thermoelectric effect. Without removing the hot air I inverted the polarity of both pairs of leads and read again. Now a negative resistance appeared while it was being heated, but after cooling down the resistance went back to positive 0.0012 ohm (as it should be, cause inverting both pairs should not make a difference).
The 4 leads are all very close together in inductor (all like 2-3 cm apart at max) and being roughly uniformly heated. There's no reason for a difference in temperature to arise in there, but there's a difference in temperature from all of them at the inductor and the other ends in the ohmmeter.
I can't heat the ohmmeter together, what can I do to compensate for the seebeck effect?
I imagine that, If the seebeck effect voltage is being added in one way and subtracted in the other, adding the resistances measured in both ways (the negative one and the large positive one) should give me the correct value.
Am I correct?