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My understanding is that if a single tone at frequency F is input to the frequency doubler, one should observe at its output in the spectrum the same tone but now at a frequency 2F.

What happens if this signal is no longer a tone?

To make it simpler and to minimize the impact of possible modulation, consider this signal now being a wide-band Gaussian noise with a bandwidth B and centered at F. I am wondering when this noise signal encounters the frequency doubler will the doubler make any practical impact on the bandwidth of such a signal.

Practically, can we expect that at the output of the doubler we will now see spectrum of the wideband white noise (with the possible realistic modulation due to the doubler spectrum) centered at 2F and with the same bandwidth B, or with bandwidth 2B, or something else?

Edit (with some additional details about the setup):

What is meant here as a frequency doubler/multiplier is a type of PiN diode, such as Cobham DH267. The carrier frequency of the wideband noise signal at the input to the doubler, F, is 6GHz, and bandwidth B of the wideband noise signal is 300 MHz.

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    \$\begingroup\$ When you refer to "the frequency doubler", what specific technique and realization are you referring to? It's possible that the answer may vary with the technique used for frequency doubling. \$\endgroup\$
    – nanofarad
    Commented Apr 6, 2023 at 15:37
  • \$\begingroup\$ Yes, highly dependent on technique. For example, an injection locked frequency doubler will output a tone with increased phase noise (and to a lesser extent amplitude noise), certainly no longer white gaussian noise. \$\endgroup\$ Commented Apr 6, 2023 at 15:50
  • \$\begingroup\$ Thanks for the comments. I added details about the type of a doubler that was considered for this question \$\endgroup\$
    – Akhaim
    Commented Apr 6, 2023 at 16:03
  • \$\begingroup\$ dh267 is a varactor, not a PiN \$\endgroup\$
    – Neil_UK
    Commented Apr 6, 2023 at 16:10
  • \$\begingroup\$ @Neil_UK I'm not sure why they call it a "varactor" - the DH267 is actually optimized to work in PIN diode multiplier circuits, as indicated by the carrier lifetime given in its datasheet. \$\endgroup\$ Commented Apr 6, 2023 at 16:19

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What you'll get is a whole lot of intermodulation distortion, which at its worst will create a wideband noise spectrum and drown out any useful signals.

A frequency doubler in its mathematically purest form is a mixer that gets fed two identical signals and multiplies them. In reality, you'll approximate the multiplication with a non-linear element (i.e. a diode) and a band-pass that removes unwanted frequency components. In effect, you purposefully distort the signal to generate harmonics and filter out the one(s) you want. To get higher-order harmonics, you can use effects such as diode snap-off, as commonly done in the PIN diode multipliers you mentioned.

If you feed a signal into such a frequency multiplier that isn't a pure sinewave, the signal will effectively turn into wideband garbage as it'll get mixed with itself, producing sum and difference frequencies of every combination of any number of points on its entire spectrum. You're essentially mixing two baseband signals together.

In short: A frequency multiplier based on a non-linear element just turns into a very bad mixer when you feed it a signal that isn't a pure sinewave.

Any mixer is also a frequency multiplier, and almost all frequency multipliers are also (bad) mixers. The difference is in the harmonic content and the filtering applied to the output.

A mixer without any filtering at its output actually produces not only the desired sum and difference frequencies, but also the doubled input frequencies. You have to add a bandpass at the output to select only the signal you're interested in.

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  • \$\begingroup\$ Perhaps for my naive understanding, but then would a purely linear element only do the mixing operation? Or is there some kind of a device that could also double the bandwidth of an input signal such as the above mentioned wide-band Gaussian white noise, in addition to the frequency mixing? \$\endgroup\$
    – Akhaim
    Commented Apr 6, 2023 at 20:52
  • \$\begingroup\$ @Akhaim A purely linear device can neither mix nor multiply frequencies - linear devices, by definition, only perform linear operations, namely amplification and phase shifting. They can't change the "shape" of the incoming superimposed sinewaves as that'd be a non-linear operation (it'd distort the signal). Look into Code-division multiple access (CDMA) if you want to distribute a signal over a wider bandwidth. \$\endgroup\$ Commented Apr 6, 2023 at 22:00

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