There's nothing mentioned of how long (=delay) the rightmost line has and of is there some load, too. I guess you want only a hint how to handle the case for the time period when there's no reflection arrived from the right end to the lumped impedance.
The incident wave which comes from the left branch to the lumped impedance is a 100 V step function. The reflection could be handled quite easily (see NOTE) if the lumped impedance was given in Laplace domain; for an inductor that is Z(s) = sL. You can consider the right line branch and the lumped impedance as a load which has Laplace domain impedance = Z(s) + Z2. Then you can apply the same reflection factor formula as you did in your previous question.
The Laplace domain reflection factor can be seen as a transfer function. The input is the incident wave and the reflected wave is the output. Multiply the Laplace transform of the input with the transfer function to get the Laplace transform of the output i,e, the reflected wave.
The inverse L-transform of the output is valid only as long as the reflection from the right end has not arrived to the lumped impedance. The reflected wave can be a tricky waveform, no matter the incident wave is a simple step. The reflection factor cannot be a single number except when the lumped impedance is a resistor.
Another approach is to go back to the basics and handle the case with differential equations. The lumped impedance also must be given as a differential equation between its voltage and current. Very likely you can finally formulate the reflection factor as a differential operator. That (Heaviside approach) is equivalent with the Laplace domain method. I skip it.
Hopefully you have about one year of (properly done) university level engineering math studies behind you to handle the things mentioned above.
If you have Zo, Z2 and the lumped impedance as numerical values you can check the result by performing a transient analysis in a circuit analysis program. There's still available Micro Cap (now freeware) which has transmission line as a component.
NOTE: It's easy only as a principle, the calculations can be massive.