A 3-phase BLDC motor, used as an alternator, outputs 3V open-circuit and 5A short-circuit at a given RPM. How can you calculate or at least estimate its useful power at that RPM if we connect it to a matched load? What is the theoretical speed-to-power law of such alternators, e.g. twice the speed - how much the power?
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About all you can say simplistically is that the maximum output power will be approximately when the voltage is half and the current is half i.e. 1.5 volts × 2.5 amps = 3.75 watts.
The above assumes the generator behaves like a voltage source with an output impedance that is resistive. It will be a tad more complex than this but, if you want a quick and simple answer, that's a reasonable estimate.
