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TonyM
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You should get 0.268 V, which you've said you do get.

You have a potential divider with 4.824 V at one end and -2.904 V at the other. So that's 7.728 V across the potential divider.

Your divider outputs (7.728 x 3900) / (5600 +3900) or 3.1725 V of the 7.728 V across it.

As the bottom of the divider is at -2.904 V, that's 3.172-2.904 = 0.268 V with respect to ground.

As the potential divider output voltage is positive, the reverse-biased diode has no real effect.

TonyM
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