Kindly any one show me the graph for inductor current and if possible explain it. I shall be very grateful!
It's quite easy to do if you use a simulator (like Micro-cap): -
Voltage in blue and current through a 2 henry inductor in red. Timebase in seconds.
The current-voltage relationship for an inductor is: -
$$V = L\dfrac{di}{dt}$$
The above can be solved for current by integrating both sides.
$$i = \dfrac{1}{L}\int{v\: dt}$$
And, for a linearly rising voltage (\$v = V_{PK}\cdot t\$),
$$i = \dfrac{V_{PK}}{L}\int{t\: dt} = \dfrac{V_{PK}}{2L}t^2$$
Circuit: -