Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with current
Search options not deleted
user 102849
Flow of electric charge - typically movement of charge carriers, such as electrons. Measured in amperes (A).
3
votes
5
answers
1k
views
Assumed wrong direction for current through voltage source on branch?
Using conventional current flow, here is my approach to the problem:
Calculate the current through the 19k resistor as just 5V over 19k and I get 263uA. … Therefore using KCL I get:
(current through 19k) + (current through 5V) = current through 300k
263uA + I = 66.67uA
I = -196uA
However when I use the simulator at falstad.com/circuit/ I get a different …
- 601
3
votes
3
answers
11k
views
If the voltage at ground is 0, why is there current flow?
So, if this is the case then why can we have current flow (at the return point)?
simulate this circuit – Schematic created using CircuitLab …
- 601