Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 193372

A well known relationship that describes the relationship between Voltage and current through a device's resistance expressed mathematically as V= IR. This formula says that voltage across the device is equal to the current through the device multiplied by the resistance.

2 votes
2 answers
126 views

Can a power supply be too powerful for a device assuming that the power supply is at operati... [duplicate]

Let’s say a device’s operating voltage is 5V and maximum current that it can draw is 5A. Is it possible for a 5V power supply to have very low internal resistance such that a device that operates at …
AznBoyStride's user avatar
0 votes
1 answer
844 views

Can you calculate internal resistance of battery by shorting it?

Can I measure the current of a battery by shorting the circuit and by ohms-law divide the voltage of the battery by the current measured to get internal resistance?
AznBoyStride's user avatar
0 votes
5 answers
260 views

Why can't you just reduce the current instead of the voltage?

Why does voltage even matter, if it's the current that goes through a circuit? I understand the relationship V = IR (I think) and that increasing the voltage (pressure) will increase the current. H …
AznBoyStride's user avatar
-1 votes
2 answers
632 views

Double the voltage did not double the amps?

I have two brand new AA batteries. I measured the voltage and current of each battery and they are both 1.5v and 5A respectively. I connected these same batteries in series and I measured the voltage. …
AznBoyStride's user avatar