Right. I got the second part exactly backwards! Thanks for clarifying. Is there a reason why you put the colors in G, R, B order in your answer? That may have been one of the factors adding to my confusion. :-)

I had to read paragraphs 2--4 several times before it clicked. "But you just said ...", no actually you didn't! I was reading one thing and interpreting another. So, please confirm this. What you are saying is: White light is actually equal actual intensity R, G and B (and of course all the others), but these diodes are weighted to show equal perceived intensity at maximum intensity.