I'd like to preface with saying that I'm quite new to this.
Given emf E = 9 V, and that both resistances are equal, R = 1 kΩ, calculate the voltmeter reading if voltmeter's internal resistance is Rv = 10 kΩ.
So far, I have calculated E * R2 / (R1 + R2) which gives me a result of 4.5V.
But, I'm not sure how to apply the internal resistance of 10k ohms. How does it affect the final result?
I'd like to preface with saying that I'm quite new to this.
Given emf E = 9 V, and that both resistances are equal, R = 1 kΩ, calculate the voltmeter reading if voltmeter's internal resistance is Rv = 10 kΩ.
So far, I have calculated E * R2 / (R1 + R2) which gives me a result of 4.5V.
But, I'm not sure how to apply the internal resistance of 10k ohms. How does it affect the final result?
I'd like to preface with saying that I'm quite new to this.
Given emf E = 9 V, and that both resistances are equal, R = 1 kΩ, calculate the voltmeter reading if voltmeter's internal resistance is Rv = 10 kΩ.
So far, I have calculated E * R2 / (R1 + R2) which gives me a result of 4.5V.
But, I'm not sure how to apply the internal resistance of 10k ohms. How does it affect the final result?
I'd like to preface with saying that I'm quite new to this.
Given emf E = 9 V, and that both resistances are equal, R = 1 kΩ, calculate the voltmeter reading if voltmeter's internal resistance is Rv = 10 kΩ.
So far, I have calculated E * R2 / (R1 + R2) which gives me a result of 4.5V.
But, I'm not sure how to apply the internal resistance of 10k ohms. How does it affect the final result?
