Timeline for What is the physical meaning of negative resistance?
Current License: CC BY-SA 4.0
26 events
when toggle format | what | by | license | comment | |
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Nov 23, 2020 at 16:58 | vote | accept | Kinka-Byo | ||
Nov 22, 2020 at 20:51 | answer | added | user136077 | timeline score: 1 | |
S Oct 4, 2019 at 23:00 | history | suggested | Circuit fantasist | CC BY-SA 4.0 |
Improved title
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Oct 4, 2019 at 22:09 | review | Suggested edits | |||
S Oct 4, 2019 at 23:00 | |||||
Oct 4, 2019 at 21:42 | answer | added | Circuit fantasist | timeline score: 3 | |
Apr 26, 2019 at 19:25 | comment | added | KalleMP | Arc discharge is modelled as a negative resistance. | |
Apr 26, 2019 at 5:43 | comment | added | richard1941 | A voltage source does not have negative resistance, it has ZERO resistance. If you have such a device, take care not to short it out with a zero ohm resistor. I cannot compute the power dissipated in such a circuit. | |
Apr 26, 2019 at 5:41 | comment | added | richard1941 | You can make your own negative resistor. Go to sparkbangbuzz.com/els/ntype-nr-el.htm | |
Apr 26, 2019 at 3:10 | comment | added | Optionparty | There are two types 'S' & 'N'. en.wikibooks.org/wiki/Circuit_Idea/… | |
Apr 25, 2019 at 23:04 | comment | added | Harper - Reinstate Monica | Meh, there's no such thing as negative resistance. It's an artifice of improperly (IMO) applying Ohm's Law to something non-linear (not resistor-like). If we flip it into conductance, you are saying something has a negative conductance, i.e. its conductance goes below 0 (below total insulator - in other words current flow induces a reverse voltage). Such a device is not a good fit for Ohm's Law. | |
Apr 25, 2019 at 22:02 | answer | added | Nightmerker | timeline score: 0 | |
Apr 25, 2019 at 18:41 | answer | added | andre314 | timeline score: 1 | |
Apr 25, 2019 at 18:00 | history | tweeted | twitter.com/StackElectronix/status/1121474137871007744 | ||
Apr 25, 2019 at 17:55 | answer | added | EE_socal | timeline score: -1 | |
Apr 25, 2019 at 17:07 | answer | added | glen_geek | timeline score: 4 | |
Apr 25, 2019 at 16:57 | history | became hot network question | |||
Apr 25, 2019 at 16:49 | answer | added | LvW | timeline score: 3 | |
Apr 25, 2019 at 16:41 | comment | added | analogsystemsrf | Minus R will provide power, not dissipate power. | |
Apr 25, 2019 at 16:39 | answer | added | LvW | timeline score: 5 | |
Apr 25, 2019 at 16:22 | answer | added | The Photon | timeline score: 4 | |
Apr 25, 2019 at 16:19 | answer | added | Mattman944 | timeline score: 1 | |
Apr 25, 2019 at 16:17 | history | edited | Marcus Müller | CC BY-SA 4.0 |
added 2 characters in body; edited title
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Apr 25, 2019 at 16:15 | answer | added | Spehro 'speff' Pefhany | timeline score: 22 | |
Apr 25, 2019 at 16:11 | answer | added | D.A.S. | timeline score: 3 | |
Apr 25, 2019 at 16:11 | comment | added | Michel Keijzers | Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-) | |
Apr 25, 2019 at 16:05 | history | asked | Kinka-Byo | CC BY-SA 4.0 |