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hontou_
hontou_
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Below is an illustration on how coincident decoding works in which the total number of gates used in the decoder can be reduced by employing two decoders in a two‐dimensional selection scheme: enter image description here

If x-output 12 and y-output 20 is both logic one, then the intersection(colored orange) will be logic 1 right? But what about the others? For example, if x-output 0 and y-output 20 is logic 0 and 1 respectively, how will the interestion(colored green) will remain disabled(logic 0) and the orange colored intersection to be the only one active(logic 1)?

Why would the intersection of logic 1 and logic 0 results in logic 0?

I thought that the intersection would mean the logic 1 being shorted to logic 0 that's why the result will be grounded(logic 0),but I doubt this since this would mean that every disabled intersections of the RAM block will be shorted and that sounds bad to me....

Below is an illustration on how coincident decoding works in which the total number of gates used in the decoder can be reduced by employing two decoders in a two‐dimensional selection scheme: enter image description here

If x-output 12 and y-output 20 is both logic one, then the intersection(colored orange) will be logic 1 right? But what about the others? For example, if x-output 0 and y-output 20 is logic 0 and 1 respectively, how will the interestion(colored green) will remain disabled(logic 0) and the orange colored intersection to be the only one active(logic 1)?

Why would the intersection of logic 1 and logic 0 results in logic 0?

I thought that the intersection would mean the logic 1 being shorted to logic 0 that's why the result will be grounded(logic 0),but I doubt this since every disabled intersections of the RAM block will be shorted and that sounds bad to me....

Below is an illustration on how coincident decoding works in which the total number of gates used in the decoder can be reduced by employing two decoders in a two‐dimensional selection scheme: enter image description here

If x-output 12 and y-output 20 is both logic one, then the intersection(colored orange) will be logic 1 right? But what about the others? For example, if x-output 0 and y-output 20 is logic 0 and 1 respectively, how will the interestion(colored green) will remain disabled(logic 0) and the orange colored intersection to be the only one active(logic 1)?

Why would the intersection of logic 1 and logic 0 results in logic 0?

I thought that the intersection would mean the logic 1 being shorted to logic 0 that's why the result will be grounded(logic 0),but I doubt this since this would mean that every disabled intersections of the RAM block will be shorted and that sounds bad to me....

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hontou_
hontou_
  • 1.1k
  • 12
  • 28

Why would the intersection of logic 1 and logic 0 results in logic 0?

Below is an illustration on how coincident decoding works in which the total number of gates used in the decoder can be reduced by employing two decoders in a two‐dimensional selection scheme: enter image description here

If x-output 12 and y-output 20 is both logic one, then the intersection(colored orange) will be logic 1 right? But what about the others? For example, if x-output 0 and y-output 20 is logic 0 and 1 respectively, how will the interestion(colored green) will remain disabled(logic 0) and the orange colored intersection to be the only one active(logic 1)?

Why would the intersection of logic 1 and logic 0 results in logic 0?

I thought that the intersection would mean the logic 1 being shorted to logic 0 that's why the result will be grounded(logic 0),but I doubt this since every disabled intersections of the RAM block will be shorted and that sounds bad to me....