Timeline for How does one know that the current is flowing downwards through the \$8 \ \Omega\$ resistor?
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 28, 2021 at 18:00 | history | tweeted | twitter.com/StackElectronix/status/1465017667350413312 | ||
| Nov 27, 2021 at 21:19 | answer | added | Circuit fantasist | timeline score: 1 | |
| Nov 25, 2021 at 21:47 | history | edited | The Pointer | CC BY-SA 4.0 |
added 44 characters in body
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| Nov 25, 2021 at 18:15 | answer | added | Spehro 'speff' Pefhany | timeline score: 4 | |
| Nov 25, 2021 at 17:37 | vote | accept | The Pointer | ||
| Nov 25, 2021 at 17:20 | answer | added | Elliot Alderson | timeline score: 9 | |
| Nov 25, 2021 at 17:16 | answer | added | Graham Nye | timeline score: 4 | |
| Nov 25, 2021 at 17:11 | comment | added | D.A.S. | Always define assumptions for conventional directions. It's all relative to these, just like gnd=0V anywhere you choose. | |
| Nov 25, 2021 at 17:10 | comment | added | cm64 | Yes exactly it is | |
| Nov 25, 2021 at 17:09 | comment | added | The Pointer | Ahh, ok, I see. So it's effectively just a placeholder assumption. | |
| Nov 25, 2021 at 17:08 | comment | added | cm64 | At the end of the analysis if that current is found negative it will mean the real direction is reverse. if found positive the assumed direction is same. At the beginning not proven. | |
| Nov 25, 2021 at 17:05 | comment | added | Andrew Morton | If the current calculation shows it is negative, then the assumption was wrong, which is not really a problem. | |
| Nov 25, 2021 at 16:55 | history | asked | The Pointer | CC BY-SA 4.0 |