Timeline for None-inverting op-amp must zero output, why not?
Current License: CC BY-SA 4.0
27 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 4, 2023 at 6:25 | history | edited | ocrdu | CC BY-SA 4.0 |
deleted 9 characters in body; edited title
|
| Apr 4, 2023 at 4:29 | history | edited | mohammadsdtmnd | CC BY-SA 4.0 |
edited title
|
| Apr 4, 2023 at 4:14 | history | edited | mohammadsdtmnd | CC BY-SA 4.0 |
added 139 characters in body
|
| Jun 17, 2022 at 15:15 | history | edited | mohammadsdtmnd | CC BY-SA 4.0 |
added 45 characters in body
|
| S Jun 17, 2022 at 15:13 | vote | accept | mohammadsdtmnd | ||
| Jun 17, 2022 at 15:10 | answer | added | mohammadsdtmnd | timeline score: -4 | |
| Jun 13, 2022 at 6:00 | history | tweeted | twitter.com/StackElectronix/status/1536226865622523906 | ||
| Jun 12, 2022 at 18:03 | answer | added | supercat | timeline score: 3 | |
| Jun 12, 2022 at 16:51 | comment | added | DKNguyen | Your equation isn't expanded correctly in the third step. ti.com/lit/sloa020 The calculation on pages 7 describes it. Where \$\alpha\$ is infinite (or ~100,1000 for a real op amp) and \$\beta=1\$ for your circuit above in Figure 1. | |
| Jun 12, 2022 at 15:01 | history | became hot network question | |||
| Jun 12, 2022 at 13:50 | answer | added | Circuit fantasist | timeline score: 2 | |
| Jun 12, 2022 at 10:57 | comment | added | Justme | "input is continually summing with its negative" is not true. Please refer to the simple rules how op-amps work. | |
| S Jun 12, 2022 at 9:07 | vote | accept | mohammadsdtmnd | ||
| S Jun 17, 2022 at 15:13 | |||||
| S Jun 12, 2022 at 9:07 | vote | accept | mohammadsdtmnd | ||
| S Jun 12, 2022 at 9:07 | |||||
| Jun 12, 2022 at 8:53 | history | edited | JRE | CC BY-SA 4.0 |
added 2 characters in body; edited title
|
| Jun 12, 2022 at 8:52 | answer | added | Andy aka | timeline score: 11 | |
| Jun 12, 2022 at 8:51 | vote | accept | mohammadsdtmnd | ||
| S Jun 12, 2022 at 9:07 | |||||
| Jun 12, 2022 at 8:49 | answer | added | devnull | timeline score: 23 | |
| Jun 12, 2022 at 8:49 | history | edited | mohammadsdtmnd | CC BY-SA 4.0 |
clarifiying gain g
|
| Jun 12, 2022 at 8:45 | comment | added | mohammadsdtmnd | @DKNguyen Why and how circuit do that? have see my calculation on question? | |
| Jun 12, 2022 at 8:34 | comment | added | DKNguyen | No, you are confusing what the opamp does with what the circuit does. The op amp alone without the feedback loop just amplifies the voltage difference between the inputs by nearly infinite gain. What I said in my first comment is what the circuit (the opamp with the negative feedback loop) does, not what the opamp alone does. | |
| Jun 12, 2022 at 8:24 | history | edited | mohammadsdtmnd | CC BY-SA 4.0 |
edited body
|
| Jun 12, 2022 at 8:18 | history | edited | mohammadsdtmnd | CC BY-SA 4.0 |
edited body
|
| Jun 12, 2022 at 7:53 | comment | added | mohammadsdtmnd | @DKNguyen If OpAmp just try to zero difference between + and -. Then in the circuit above flip the OpAmp around horizon. Again output must follow the input, but it won't! | |
| Jun 12, 2022 at 7:40 | comment | added | DKNguyen | "then it must become zero on the output" No, it must become zero between the input and the output. When + input higher than - input, the opamp increases the output. WHen + input is lower than the output, the opamp decreases the output. | |
| Jun 12, 2022 at 7:16 | answer | added | Kuba hasn't forgotten Monica | timeline score: 8 | |
| Jun 12, 2022 at 7:00 | history | asked | mohammadsdtmnd | CC BY-SA 4.0 |