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The original transfer function is I(s) over V(s) for a basic circuit that contains a resistor, inductor and a capacitor with a voltage source (Basic RLC circuit) where R is the resistance of the resistor, C is the capacitance of the capacitor and L being the inductance of the inductor.

Why does Vc(s) = I(s) / s when trying to convert the transfer function to be Vc(s) over V(s)?

My college uses the Laplace table without any complex integration needed for now so answers using the Laplace table would be better and be greatly appreciated

enter image description here

enter image description here

The original transfer function is I(s) over V(s) for a basic circuit that contains a resistor, inductor and a capacitor with a voltage source (Basic RLC circuit) where R is the resistance of the resistor, C is the capacitance of the capacitor and L being the inductance of the inductor.

Why does Vc(s) = I(s) / s when trying to convert the transfer function to be Vc(s) over V(s)?

My college uses the Laplace table without any complex integration needed for now so answers using the Laplace table would be better and be greatly appreciated

enter image description here

The original transfer function is I(s) over V(s) for a basic circuit that contains a resistor, inductor and a capacitor with a voltage source (Basic RLC circuit) where R is the resistance of the resistor, C is the capacitance of the capacitor and L being the inductance of the inductor.

Why does Vc(s) = I(s) / s when trying to convert the transfer function to be Vc(s) over V(s)?

My college uses the Laplace table without any complex integration needed for now so answers using the Laplace table would be better and be greatly appreciated

enter image description here

enter image description here

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Why is the voltage across a capacitor in the Laplace domain equals I(s) / s?

The original transfer function is I(s) over V(s) for a basic circuit that contains a resistor, inductor and a capacitor with a voltage source (Basic RLC circuit) where R is the resistance of the resistor, C is the capacitance of the capacitor and L being the inductance of the inductor.

Why does Vc(s) = I(s) / s when trying to convert the transfer function to be Vc(s) over V(s)?

My college uses the Laplace table without any complex integration needed for now so answers using the Laplace table would be better and be greatly appreciated

enter image description here