I have an Exar XR2206 to generate triangle wave with single supply Vcc. This wave has peak value 12 volt and 0 volt.
How to make this IC operate in split-supply?
Hence I got triangle wave with peak value +6 Volt and -6 Volt.
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\$\begingroup\$ Are they still selling those? (I thought they went obsolete.) \$\endgroup\$– George HeroldCommented Oct 15, 2014 at 12:46
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\$\begingroup\$ @GeorgeHerold They've been obsolete for a solid 5 years now. \$\endgroup\$– Matt YoungCommented Oct 15, 2014 at 12:53
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\$\begingroup\$ I still find it on local market. \$\endgroup\$– smsidkiCommented Oct 15, 2014 at 12:59
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2 Answers
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The XR2206 will operate just fine from split supplies. All you have to do is tie all ground pins to V-. See pages 10 and 11 of the datasheet.
answered Oct 15, 2014 at 12:14
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\$\begingroup\$ Oh, I got it. How about pin 12 (ground pin) of this IC? Should I connect it to negative voltage supply? \$\endgroup\$– smsidkiCommented Oct 15, 2014 at 12:22
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\$\begingroup\$ Tie all ground pins to V-. \$\endgroup\$ Commented Oct 15, 2014 at 12:24
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\$\begingroup\$ I have dual supply with three pins, +V, 0 V, and -V. If all ground pins are tied to V-, how about pin 0 V of the supply? Just left it opened? \$\endgroup\$– smsidkiCommented Oct 15, 2014 at 12:35
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\$\begingroup\$ Per the datasheet, the resistor tied to the MO pin can be tied to 0V. \$\endgroup\$ Commented Oct 15, 2014 at 12:38
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\$\begingroup\$ Does it mean i need to tie 0V to the node between resistor 5.1 kOhm? \$\endgroup\$– smsidkiCommented Oct 15, 2014 at 12:51
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Use a level shifting op-amp circuit to subtract 6V from the signal or, if the lowest frequency you need is hundreds of Hz a simple high pass RC filter with a cut-off around a few Hz would remove the DC level and centralize it without altering the shape too much.
Alternatively, if you didn't mind losing half the amplitude you could use this circuit: -
simulate this circuit – Schematic created using CircuitLab
answered Oct 15, 2014 at 11:56
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\$\begingroup\$ I need a 10 kHz triangle wave. I think level shifting op-amp is a good option. \$\endgroup\$– smsidkiCommented Oct 15, 2014 at 12:14
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\$\begingroup\$ @Sidqi to be honest I think Matt's answer is probably the way forward unless you don't (or can't) have a -6V supply. \$\endgroup\$– Andy akaCommented Oct 15, 2014 at 12:19
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\$\begingroup\$ Yes, i agree. Thank you very much for your suggestion, Sir. \$\endgroup\$– smsidkiCommented Oct 15, 2014 at 12:25