1
\$\begingroup\$

I've looked around this site but I haven't been able to figure out why this oscilloscope seems to have such a high sampling rate "Repetitive mode: 20GSa/S" and be relatively cheap: http://shop1.usbdso.com/MSO-9201-with-Logic-Analyzer-MSO-9201wla.htm

Can someone explain?

Thanks

\$\endgroup\$

1 Answer 1

Reset to default
6
\$\begingroup\$

This is for a repetitive signal like a standing sine wave.

When I buy a scope I always look for is the real-time sample rate which indicates the maximum rate an incoming signal can be acquired in a single-shot acquisition. On the other hand, repetitive sample is a method of reconstructing a signal based on a series of triggered waveforms that are each acquired in single-shot mode. The advantage of repetitive mode is that it offers a higher effective sample rate. The downside, however, is that it takes more time and is applicable only for repetitive signals. This scope has a real time rate of only 200MSa/s - far from the 20GSa/s.

In general I hate using PC based oscilloscopes and would tell you to go for something like this instead if you're in the market for a scope to use. Unless you are really strapped for money and need the 200MHz bandwidth or really need the deep sample rate.

\$\endgroup\$
5
  • 1
    \$\begingroup\$ Also called equivalent-time sampling. \$\endgroup\$
    – user36129
    Commented Mar 31, 2014 at 9:15
  • \$\begingroup\$ Hi Gonzik, what does the equivalent sample rate mean in the following link? rigolna.com/products/digital-oscilloscopes/ds1000e \$\endgroup\$
    – david
    Commented Mar 31, 2014 at 21:19
  • \$\begingroup\$ Equivalent-time and repetitive sample are the same thing as pointed out by user36129 above. \$\endgroup\$
    – EasyOhm
    Commented Apr 1, 2014 at 4:00
  • 1
    \$\begingroup\$ Short version: Lies from the marketing department. \$\endgroup\$
    – John U
    Commented Apr 1, 2014 at 7:39
  • \$\begingroup\$ Ok now, I get user36129. Thanks everyone for your help! \$\endgroup\$
    – david
    Commented Apr 1, 2014 at 13:08

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.