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I am using a power supply set to 9V and current limited at 0.6 amps to power a radio which includes a RF amp (using a transistor) and an audio amp. If the current limit is reached the device shuts off and beeps--it is an older power supply.

The power supply is a GoldStar Gp-105.

GoldStar Gp-105

My circuit is:

Schematic

The input for the 9V battery is labelled as an antenna terminal (it was due to PCB printing requirements at my school).

I tried switching the power supply out with a 9V battery and I get awful noise in my speaker which is a 8 ohm 1 watt speaker.

Why is the 9V battery not equivalent to the power supply? It works when I put a small 800 ohms resistor, but the sound is very low.

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  • \$\begingroup\$ It sounds like your supply is oscillating, and that's being amplified by your audio amp. Do you have an oscilloscope you can use to test? \$\endgroup\$ Commented Oct 29, 2015 at 15:03
  • \$\begingroup\$ Are you saying you get a noise with the PSU but not with a battery? \$\endgroup\$
    – user1844
    Commented Oct 29, 2015 at 15:03
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    \$\begingroup\$ Did you measure that the 9V from the battery stays 9V when the circuit is connected ? If it's a full battery that will probably be the case. So no problem there. But this is an AM radio. AM radios work better when they are grounded. The supply provides this, the battery does not. Try with the battery but make a connection between the ground of your radio and the ground on the supply. \$\endgroup\$ Commented Oct 29, 2015 at 15:04
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    \$\begingroup\$ Try putting a very large capacitor in shunt with your battery. A small battery could have a relatively large impedance. Motor boating can be caused when an amp drives a speaker, which pulls current from the battery, which sags, which generates a spurious input to the amplifier, which generates an output ... and so on. It may not be that, but it's worth checking. It may be your battery is too weedy to provide the current the amp needs, that would not be cured by a large capacitor. \$\endgroup\$
    – Neil_UK
    Commented Oct 29, 2015 at 15:48
  • \$\begingroup\$ Nike: I do have an oscilloscope to test this, and I've found that the signal from the diode is eaten up. \$\endgroup\$
    – Klik
    Commented Oct 29, 2015 at 20:53

2 Answers 2

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The difference is that the battery has a higher impedance, especially at the frequencies you are using, than the nicely regulated power supply.

Somewhere in your circuit, probably in the early stages of the audio amplifier, it is making the assumption that ground and power are equivalent for AC signals. From this you can derive that the impedance of the power supply is assumed to be 0. Of course no supply has exactly 0 impedance, but the regulated power supply is a lot closer to this than the battery, and that difference is enough to upset your circuit.

To fix this and to verify this is really what is happening, put a decent size cap across the battery. Try something like a few 100 µF at least, but a mF or more would be better. It would also be a good idea to put a 1 µF ceramic cap across the power feed right where it enters the circuit. That will lower the impedance at high frequencies, something the large electrolytic cap can't do.

If a cap across the battery fixes this, and I think it will, then your circuit was poorly designed. Caps on the power supply should have been included as part of the circuit in the first place, so that it doesn't rely on the impedance of some external source.

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  • \$\begingroup\$ I don't completely understand what you mean when you say put a cap across the power feed. I have a 1uF cap from the positive terminal of my battery going to ground already, though I'm using an electrolytic one. I will try your suggestion of using a 100uF cap. \$\endgroup\$
    – Klik
    Commented Oct 29, 2015 at 21:06
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A battery will output most of the time a constant voltage. A PSU converts 110/220 AC voltage into your 5VDC (or whatever voltage), and that process isn't perfect, so a PSU can't output trully constante voltage. Here is a image that ilustrate the AC/DC convertion process.

graph
(source: uonbi.ac.ke)

So when you are working with amplifier, your ripple voltage will also get amplified, and that may cause trouble on your circuit. A way to maybe work this problem out is to put a capacitor in your PSU output, the higher its value the best, but that may have some other issues, like taking some time for your voltage to get stable, cause it will need to charge the capacitor for that.

For more info on the topic I suggest getting a book that talks about voltage regulation and power supplies. Most basic eletronics book will have this.

And of course this dosen't happen to batteries cause they output "pure" DC voltage, not a transformed from AC one.

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  • \$\begingroup\$ This doesn't explain my problem though, because when I use the power supply, my circuit works great, but when I use the battery, it fails. \$\endgroup\$
    – Klik
    Commented Oct 29, 2015 at 21:08
  • \$\begingroup\$ Oh damn, I've problaby misread that, haha sorry. \$\endgroup\$ Commented Oct 29, 2015 at 23:28

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