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im trying to use a 0-7V control signal to switch an NPN controlling a LED but then using collector of the NPN to switch a PNP. So when control V is low NPN LED is on and PNP LED is off and when control V is High NPN LED is off and PNP LED is on. Is the below circuit a good way of doing this? i have imagined this circuit in my head and cant find anything similar, maybe for good reason?

enter image description here

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    \$\begingroup\$ That circuit will turn both on and off at the same time. You need one NPN for the red LED and you need your whole circuit - NPN and PNP - without the red LED to switch the green. \$\endgroup\$ – Transistor Oct 6 '16 at 11:11
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Your circuit will turn both LEDs on or both LEDs off.

This will solve that:

schematic

simulate this circuit – Schematic created using CircuitLab

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  • \$\begingroup\$ this looks great too. will test both out. many thanks! \$\endgroup\$ – Nanchild Oct 6 '16 at 11:45
  • \$\begingroup\$ I can guarantee you that this one will suit you better than Rohat's one as his one is just a voltage buffer. This one has gain making it switch in a nicer way. \$\endgroup\$ – Bimpelrekkie Oct 6 '16 at 11:47
  • \$\begingroup\$ This one is better than mine, of course. As I said before, I thought that the input has the same level as Vcc. \$\endgroup\$ – Rohat Kılıç Oct 6 '16 at 11:52
  • \$\begingroup\$ that really is a lovely circuit! many thanks to you both, i can now see why mine didnt work in the first place! \$\endgroup\$ – Nanchild Oct 6 '16 at 11:53
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    \$\begingroup\$ @anhnha You mean both LEDs will be on, true but since R3 is 10 k ohm the current through D1 will be significantly less than the current through D2 making D1 significantly less bright than D2. If that bothers you you could add a resistor in parallel with D1 to make the voltage across D1 low enough for it not to light up. \$\endgroup\$ – Bimpelrekkie Oct 14 '16 at 21:04

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