Reduce to line level from 8 ohm, 6 w stereo [closed]

I had a look at another Exchange question, and couldn't quite understand.

I have a set of cheap speakers, 8ohms each with a combined output of 6 watts.

If sqrt(6w/8Ω) = 0.866 v, and the post says line level is approximately 1 volt, what should my amperage be?

How can I calculate for an appropriate resistor?

I have about 10 150Ω resistors at home... will wiring them half and half between speakers attenuate the signal? How many do I need of each?

EDIT (CLARIFICATION):

I want to know how to calculate the resistance needed to reduce a powered signal (6w) to line level.

closed as unclear what you're asking by Trevor_G, Enric Blanco, PeterJ, Dmitry Grigoryev, winnyJun 8 '17 at 10:36

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• I think your calculation's a bit wonky. 0.866V into 8 ohms won't give you 6W. – Simon B Jun 1 '17 at 13:59
• It ought to be $\sqrt(3W * 8R)\approx5V$, $I\approx0.6A$ per speaker. However, no idea what you are asking re the resistors.....question is unclear. Voting to close. – Trevor_G Jun 1 '17 at 14:10
• You seem to be confusing all sorts of nomenclature. Line level is not used to drive speakers, it is used to send audio signals to devices expecting line-level (nominally 1-2Vpp) inputs, like power amps (used to drive speakers), audio interfaces, or studio effects units. – Chris M. Jun 1 '17 at 14:57
• @ChrisM. Hence my question says reduce to line level, not from line level. I have speakers that are powered, but I want to cut the wires to them and output them to a jack at line level. – yeeeeee Jun 2 '17 at 6:24
• @Trevor, I don't come from any electrical background at all. Don't "vote to close" because of my naivety. – yeeeeee Jun 2 '17 at 6:25