0
\$\begingroup\$

R2=100 ohm , R3=150ohm , R4=220ohm , R6=330ohm

I calculate equivalent resistance like this

150*100/150+100=60 ohm

220*330/220+330=132 ohm

60+132=192 ohm

can you tell me whether it true or wrong?

\$\endgroup\$
2
  • \$\begingroup\$ R3 is not parallel with R2. R3 is in parallel with R2+(R4||R6) \$\endgroup\$
    – G36
    Commented Feb 17, 2018 at 12:25
  • 1
    \$\begingroup\$ As seen from source terminals? In that case it'd be R3 || (R2 + (R4 || R6)) \$\endgroup\$
    – Deep
    Commented Feb 17, 2018 at 12:29

2 Answers 2

4
\$\begingroup\$

This only looks difficult because of the layout. If you would take the time to redraw it you could see that this is very simple to solve.

schematic

simulate this circuit – Schematic created using CircuitLab

\$\endgroup\$
2
\$\begingroup\$

R4 and R6 are in paralell, so calculate it first. Then, do the series with R2, and finally, the paralell with R3. So:

1/Ra = 1/R4 + 1/R6
Ra = (R4*R6)/(R4 + R6)
Rb = Ra + R2
Rtotal = (Rb*R3)/(Rb + R3)
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.