I am designing anenergy regeneration system using a pulley attached to the wire rope of a track elevator using a 3:1 sprocket ratio I am getting around 670 RPM`s I am using two 6 volt lead acid batteries in series match to a 12 volt pure sine wave inverter I am trying to figure out what alternator/ generator should I use that will charge my system and knowing the 670 RPM what output can I expect
3
-
2\$\begingroup\$ Two 6 volt batteries in series give you 12 volts. That won't run a 24 volt inverter (assuming you mean an inverter that requires a 24 volt power source). \$\endgroup\$– Peter BennettCommented Sep 22, 2019 at 4:15
-
\$\begingroup\$ For one approach to designing a custom alternator for non-standard RPMs, look at small wind turbine expertise, e.g. here scoraigwind.co.uk/contents \$\endgroup\$– user16324Commented Sep 22, 2019 at 14:13
-
\$\begingroup\$ Yes sorry I meant a 12 volt inverter \$\endgroup\$– Luis CidCommented Sep 23, 2019 at 0:56
Add a comment
|
1 Answer
\$\begingroup\$
\$\endgroup\$
670 rpm is about half the minimum an alternator needs.
If you look on a car the alt pulley diameter is about 1/3 of the crank pulley diameter.
This means that when the car engine is idling the alternator can cover the demand.
But at max engine speed the alt must not exceed its max rpm - usually about 10000 rpm so the pulley ratios must be checked.
Have seen an alternator seized due to excess speed (not bearings but rotor welded to stator) - owner did a conversion on a v6 motor and did not check the pulley sizes...
answered Sep 22, 2019 at 6:36