USB Type-C is able to provide up to 5A. When I look at trace width guidelines, I find my traces have to be 110mil/2.79mm wide for 1oz default traces. The thing is, 100mil is literally more than 5 pins of Type-C including distance between them. It's like 1/3 of the entire Type-C connector. I've never built circuit that can have such current, so I'm looking for advice from more experienced people.
What would be the correct way to implement Type-C port with high current? At least 3A, up to 5A would be best. Type-C has 4 VBus pins. So this is my list of the questions, I would appreciate, if you could give an advice and explain why it has to be certain way, please.
- Do I need to connect all VBUS pins together on my PCB?
- How wide should my traces be?
- They can't be wide near the pins themselves, how do I organize it then so that I don't burn anything?
Unfortunately, googling it only gives general guidelines like "so many amps - trace this wide". I tried several synonymous searches, but couldn't find any lead. It doesn't really discuss the narrow-pin-bottleneck of the Type-C port. I'm pretty sure it's hidden somewhere in power delivery specs or something, but I couldn't google out the exact part, and from what I remember, USB specs now compete with "War and Peace" in volume. But a link to the spec, if it contains an answer to my question, would also be appreciated. Thank you!