In the following picture current is flowing through coil 1. Let's assume that current is increasing linearly in coil 1. Then emf induced in 2nd coil be will constant and having some negative value. What would be the flux in coil 2? How it could be interpreted in graphs and what's reason behind the behaviour?
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What would be the flux in coil 2?
The flux in coil 2 is produced entirely from the current flowing in in coil 1 hence, if you know what the flux coupling factor (k) is, coil 2's flux is coil 1's flux multiplied by k.
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\$\begingroup\$ Does emf have any effect on flux? As the current in coil 1 is increasing or decreasing, consequently the emf in coil 2 will be negative or positive due to which current direction changes and flux in coil 2 will also change... \$\endgroup\$– AhsanCommented Oct 5, 2020 at 15:16
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1\$\begingroup\$ Only current in coil 2 will affect the flux. An open circuit emf is of no-consequence. \$\endgroup\$– Andy akaCommented Oct 5, 2020 at 15:21
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\$\begingroup\$ Let the current in coil 1 is increasing linearly. The current in coil 2 will be in opposite direection so that magnetic field will tend to oppose the magnetic field of coil 1. As the magnetic flux will be in opposite direction in coil 2. In that case the coupling coefficient is also valid? How? \$\endgroup\$– AhsanCommented Oct 5, 2020 at 15:24
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\$\begingroup\$ @Ahsan I'm sorry but this site isn't a forum and you now appear to evolving what you want to know into much more seriously mathematical areas. I'm just saying this in case you thought stack exchange was some coaching site. To answer this you need to look at the theories of mutually coupled inductors. Sure the net flux will lower in coil 2 when current is drawn from coil 2 but the current in coil 1 will also increase to counter flux_2 and that will tend to try and cancel the negative effects of coil 2's flux. It gets mathematical pretty much straight away and somewhat non-intuitive. \$\endgroup\$– Andy akaCommented Oct 5, 2020 at 15:56
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\$\begingroup\$ k will remain constant throughout. Voltage across coil 2 will drop with coil 2's current but k remains fixed. The voltage across coil 2 is directly a measure of the net flux coil 2 sees. \$\endgroup\$– Andy akaCommented Oct 5, 2020 at 16:02