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The output impedance mentioned, but how does this translate to maximum current? What happens if you short circuit the output of a function generator?

Let's take the XR-2206 for example.

The datasheet states an output impedance only for triangle wave of 600 ohms and nothing for the other wave forms.

Why is this 'never' important?

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  • \$\begingroup\$ please post a link to the datasheet that you are referring to \$\endgroup\$
    – jsotola
    Commented Jan 10, 2021 at 20:00
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    \$\begingroup\$ The XR-2206 is a chip to implement a part of a device called function generator, so there should be some circuitry between a chip and output connector to do some buffering and amplification. \$\endgroup\$
    – Justme
    Commented Jan 10, 2021 at 20:02
  • \$\begingroup\$ pdf1.alldatasheet.com/datasheet-pdf/view/80496/EXAR/XR2206.html \$\endgroup\$
    – Niels
    Commented Jan 10, 2021 at 20:03
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    \$\begingroup\$ Because you're not expected to connect something to it with a lower input impedance than specified. \$\endgroup\$
    – DKNguyen
    Commented Jan 10, 2021 at 20:39
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    \$\begingroup\$ Output it is protected by an internal resistor, after the out amplifier \$\endgroup\$
    – GR Tech
    Commented Jan 11, 2021 at 2:04

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There is output impedance mentioned, but how does this translate to max. current?

I = V/R, so assuming you know the voltage you can calculate the current.

Why is this 'never' important?

If you're going to be driving a load then presumably you would use a driver IC or amplifier suitable for that load, making the current limit irrelevant.

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    \$\begingroup\$ This is not very clear. What is the 'R' in this example? The load or the output resistance of the signal generator? \$\endgroup\$
    – Elliot Alderson
    Commented Jan 10, 2021 at 20:52

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