At an exam, I was asked the following question: A stepper motor has the greatest torque on its shaft in the 'halfstep/full step'. Everywhere on the internet it says that full step gives the most torque. This was also the answer I indicated. I have already emailed this to my professor but he claims that: at half step 2 coils are energised, which gives a field that is the vectorial sum of the two separate fields. Therefore, this field is stronger than the field of 1 coil. Is this correct? Does anyone know how I can prove him wrong? Thanks in advance
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\$\begingroup\$ Where on the internet does it say what you say it says? Links please. \$\endgroup\$– Andy akaCommented Dec 24, 2021 at 16:38
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3\$\begingroup\$ It depends how half stepping is implemented so it may or may not be true. In any case field strength is not the only factor determining torque. \$\endgroup\$– user16324Commented Dec 24, 2021 at 18:33
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1\$\begingroup\$ duplicate of electronics.stackexchange.com/q/316462/1743 ? \$\endgroup\$– Ben VoigtCommented Dec 24, 2021 at 19:21
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1\$\begingroup\$ If you are specifically interested in holding torque when the motor is still, then sure, you could energize A=100% B=100%, which would in principle be more than the holding torque at a full step position when only one coil was A=100% B=0%. But modern drivers combine them as vectors, in which case the answer would be no. \$\endgroup\$– Pete WCommented Dec 25, 2021 at 1:58
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Stepper motor only ..., this note figure 9
With stepper driver ... From this note , see "selecting driver mode", end of paper.
Seems to be a little error (or comparison) in legend ... for figure 12.
for half-stepping ... (comparing figure 10 and 12) ...
<<< Compared to full stepping (refer to figure 10 for the same driving conditions), a slightly-higher torque at low speed and a small decrease at higher step rates.>>>
Not really very significant with this driver.
