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Results tagged with circuit-analysis
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user 166884
Circuit (Network) analysis is the process of finding the voltages across, and the currents through, every component in the network. Consider using in conjunction with tags for the particular analysis technique(s) in question: "nodal-analysis", "mesh-analysis", "superposition", etc.
1
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rc circuit for electrical noise: why are these circuits similar?
In both the circuits, shorting the AC source and the switch in ON position, make both RC and L shorted. Thevenin eq. impedance is zero in both the cases, when looking from Vo end.
- 11k
0
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Second order opamp circuit problem
It's just a typo. Its obvious from equation 2. They meant:
$$\frac{dv_1(0+)}{dt} = \frac{-v_0(0+)}{C_2R_2}=0$$
That's why all \$\frac{dv_1(0+)}{dt}\$ terms vanished from equation 1, on last simplifica …
- 11k
1
vote
Accepted
Applying superposition in circuit analysis
You have a network that consists of linear elements and independent voltage sources, so why not? You can apply superposition theorem.
In your circuit, superposition theorem can be used to calculate cu …
- 11k
3
votes
Accepted
How many nodes?
There are four points in this circuit where voltages are different. They can be referred to as nodes. Whenever we say "voltage" at a point, the reference point is ground of that circuit. Ground is a …
- 11k
2
votes
Mosfet Analysis
The "seemingly equivalent circuit " you have re-drawn is wrong. You can't split R into two Rs like that. Anyway you found Vgs = Vds using it, because you took voltage drop across R to be same in both …
- 11k
2
votes
Accepted
3 Diodes-circuit analysis
All diodes are assumed to be ideal.
When Vi > 3V, D3 started conducting.
When it started conducting, Vo = VA will be at \$(Vi + 3)/2\$ volts.
Which means, when Vi = 6V, VA = 4.5V. D1 does not stop …
- 11k
1
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How do I find the Thevenin resistance and its corresponding voltage?
Is the 16 ohm not part of the resistance calculations anymore
You can disregard it, because the other end is open, it doesn't let any current flow through it.
do i just add r3 r5 r2 and r4 in serie …
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1
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How to calculate the Impedance of a circuit
First you identify the concerned impedance is across which two points. Let's take the first circuit. The total load impedance seen by the voltage source will be across the voltage source, ie., across …
- 11k
3
votes
Why is there negative sign as well as positive sign with currents flowing into node for KCL
Signs of current in a circuit are just conventions chosen at your convenience.
I can say a current of \$1A\$ flows from node A to B. I can also say that current of \$-1A\$ flows from node B to A. Both …
- 11k
2
votes
Base resistor in open collector
Adding to the answers of others:
Your micro-controller has some internal pull-up inside. So yeah some small current will flow to the ground via the transistor, when Vin is pulled high. Now you can ea …
- 11k
2
votes
Accepted
Series RLC circuit problem
The problem happened when you differentiated the both sides of the equation. 100 Volts, which is a constant, became 0 in the left hand side of equation after differentiation. Don't you think there is …
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1
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Output impedance of circuit with ideal op amp
When saturated, the output of the opamp no longer responds to changes in output ( Flat transfer curve). Means, \$ A_{vo} = \frac {\delta V_o}{\delta V_i} = 0 \$. So now you can substitute it in your e …
- 11k
1
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Accepted
How can I solve this exercise on Operational Amplifiers?
The second part of the solution of the exercise says,
\$\frac{R_2}{R_3} = \frac{R_1}{R_4} = 1\$
From this, its clear that they assume the circuit to be a unity differential amplifier.
So it m …
- 11k
1
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Why is there a sudden change in current between \$t=0^{-}\$ and \$t=0^{+}\$ when an active i...
Just like Charge should be conserved when two capacitors are brought parallel,
Flux should be conserved when two inductors are brought in series.
Equate the flux before and after switch was opened:
…
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1
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How to Find DC Step Response of Semi-Parallel RLC Circuit
one more for you:
\$i_{cR_2} = C \frac{dV_c}{dt} = \frac{V_a-V_c}{R_2} = f(V_a,V_c) ----(3) \$
Now you have three independent equations and three unknowns (\$i_L,V_c,V_a\$) to solve everything.
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