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PSU Datasheet
(source: tomshardware.com)

While i am quite familiar with most of the specifications on a power supply unit like this one, I fail to understand what is going on with the negative voltages. I have a few theories, though.

  1. The negative voltages are just the grounds which correspond to the matching positive voltages.
  2. These are actually at negative potential relative to ground

However, neither of these explanations really explains why you would have these outputs sourcing half an amp of current.

If they were the grounds, then they would have to sink just as much current as the positive side was putting out. In addition, there isn't a negative output to match with every positive output.

However, if they really were at a negative relative potential to ground, I would not expect them to be sourcing current, because that current would have to flow against a voltage differential.

So, what is going on with these negative voltages?

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  • \$\begingroup\$ Somewhat useful to note is that in the current ATX spec, neither -5 nor -12V are mandatory supplies and are not actually present on recent PSU designs anymore. \$\endgroup\$
    – user36129
    Commented Mar 13, 2015 at 13:57

3 Answers 3

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It would probably make more sense if the label were adjusted sligthly: enter image description here

Those -5V and -12V outputs really are negative voltages (not the ground returns for +5V and +12V) and they do sink current.

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    \$\begingroup\$ This is the correct answer. They're not grounds, they're negative with respect to ground, and current flows from the ground to the negative rail. They're not much used any more but still required by the specification. \$\endgroup\$
    – pjc50
    Commented Mar 13, 2015 at 13:56
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    \$\begingroup\$ So, if you wanted to have a 24V supply, you could use the difference between the +12V and -12V lines as a 0.8A 24V supply? Am I understanding this correctly? \$\endgroup\$
    – Tustique
    Commented Mar 13, 2015 at 14:21
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    \$\begingroup\$ Yes you are correct. \$\endgroup\$
    – brhans
    Commented Mar 13, 2015 at 14:24
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    \$\begingroup\$ @user38168, you could, and it's been done, but if you're repurposing ATX supplies a bit of googling first wouldn't be a bad idea - you often need a minimum load on the +5V line for the other lines to be properly regulated, for example. \$\endgroup\$
    – Chris H
    Commented Mar 13, 2015 at 21:33
  • \$\begingroup\$ @ChrisH, I have already done plenty of googling. I wouldn't be here if I hadn't. \$\endgroup\$
    – Tustique
    Commented Mar 14, 2015 at 21:25
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I don't know anything about this specific power supply. However, my guess is that:

  • There is one ground for everything
  • -5V literally means a line that has a voltage of -5V relative to ground
  • (-5V, 0.8A) really means that the -5V can sink 0.8A of current.

For another example, take a look at the LM79xx datasheet. These are linear voltage regulators that output a negative voltage. However, on the front page of the datasheet, it says:

The LM79XX series of 3-terminal regulators is available with fixed output voltages of -5V, -8V, -12V, and -15V [...] and is capable of supplying 1.5A of output current.

However, these would typically sink up to 1.5A of current. I imagine that supplying current either means sinking or sourcing, depending on the voltage level - you could say that it's the magnitude of the current.

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Older computers needed negative voltage for certain functions. The biggest one that comes to mind is RS-232 signaling, which used +12/-12 volts. Almost nothing (if anything at all) in a modern computer uses negative voltage. Because of this, the voltage regulators for the negative voltages are much smaller than the regulators for the more commonly used positive voltage rails.

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