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enter image description here enter image description here As you can see this a transitor AND gate and yet the LED glows when only one input is high, passing the current essentially through the base and emitter. I think I fried (I think) my transistor since I'm running the transistor at the absolute maximum (this is a 2n2222a and that is a 7806 voltage regulator) bar voltage.

I need to know the effect of exceeding the each absolute maximum and whether these are salvageable.

Also, what happens in the transistor when you exceed absolute maximum values (in the NPN junction, in terms of holes and electrons and why the damage is permanent)

[enter image description here]

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    \$\begingroup\$ "As you can see" No, we can't see. You didn't post a schematic and the photo is poor: it is impossible to see the connections of the parts on your breadboard, nor how they are powered (only the red wire from the positive terminal of the battery is shown, where does the negative go?) \$\endgroup\$ Commented Aug 5, 2015 at 14:14
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    \$\begingroup\$ If you overheat the semiconductor too much then the electrons fall into the holes and can't get out. \$\endgroup\$ Commented Aug 5, 2015 at 14:41
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    \$\begingroup\$ VCBO collector-base voltage open emitter − 75 V VCEO collector-emitter voltage open base − 40 V VEBO emitter-base voltage open collector − 6 V IC collector current (DC) − 600 mA ICM peak collector current − 800 mA IBM peak base current − 200 mA Ptot total power dissipation Tamb ≤ 25 °C − 500 mW Tstg storage temperature −65 +150 °C Tj junction temperature − 150 °C Tamb ambient temperature −65 +150 °C Those are the stated max values on the data sheet, which one of this max values do you think you are running at or exceeding?? because I do not think you are exceeding any \$\endgroup\$
    – Kvegaoro
    Commented Aug 5, 2015 at 15:49
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    \$\begingroup\$ @SpehroPefhany No it's really the other way around! ;-) If you overheat the semiconductor electrons begin to jump out of holes (maybe because it's too hot there :-D ) \$\endgroup\$ Commented Aug 5, 2015 at 15:49
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    \$\begingroup\$ Clearly, the schematic does not match the breadboard. Where's the 7806 regulator, the 9V battery, the second transistor? And with the one-transistor circuit you've drawn, why do you think the LED should NOT be lit? \$\endgroup\$
    – Dave Tweed
    Commented Aug 5, 2015 at 16:03

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I need to know the effect of exceeding the each absolute maximum and whether these are salvageable.

Exceeding absolute maximum ratings is always bad, that's why they are called absolute. And almost every datasheet I've ever seen states something like this:

enter image description here

The amount of damage can vary from a negligible (for your application) degradation of the performance of the device to a complete fireworks show. Of course it's intuitive that the largest the overstress and the longer it is applied the worse are the consequences.

Anyway, once you go beyond the maximum ratings, even for the tiniest amount and for the smallest time interval, you cannot trust the datasheet any longer. This doesn't mean it is sure 100% your device has been damaged, but it may well be. You could be lucky and have a part which is, due to manufacturing spread, more capable than the average of its kind, but there is no way to know. That is, for small over-stresses such a "stronger specimen" could survive with no damage whatsoever, but to be sure it really wasn't damaged you'd have to fully characterize the device again, i.e. you should repeat the same procedure the manufacturer does when he collects the data to compile the datasheet.

Of course, at hobbyist level such procedure is almost infeasible, so you are left with simple testing, such as checking whether the junctions of a BJT still behave as diodes using a multimeter with diode-checking capability. Even if you have a multimeter with a BJT tester this will be almost useless, since it would measure the actual hFE under some unknown conditions, and that will tell you nothing about whether the performance was better before the overstress "accident".

You could do some simple functional test, i.e. plug the BJT into some simple circuit that you know it's not critical, i.e. it doesn't rely on tight part specifications (such as using the BJT to switch on a LED), and see if it works. That will tell you that the BJT is still "usable", for some foggy definition of usable, of course.

Also, what happens in the transistor when you exceed absolute maximum values (in the NPN junction, in terms of holes and electrons and why the damage is permanent)

The exact process that brings a device to be damaged is a very broad area: you may want to google for "BJT failure modes" and see what pops up.

And "why the damage is permanent": why do you expect a physical object not to have limits? If I load a nylon rope too much it breaks. Neglecting how exactly the rupturing process evolves, would you expect a rope to be indestructible? The same is for electronic devices. The maximum ratings are just that: the limits beyond which the device is likely to break.

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  • \$\begingroup\$ Switched to 5 volts, no fireworks in my house thank you. I just tried connecting an LED to the emitter and connecting the be to positive while leaving the collector hanging ; the led glowed. Since the emitter is output having even a small current can turn transistor logic gates on. Is there a way around this? \$\endgroup\$
    – Vrisk
    Commented Aug 5, 2015 at 16:19
  • \$\begingroup\$ @AnirudhGanesh - Please, go find somebody who can explain transistors to you. Your concepts are so out of touch with reality that I don't know if anybody here can help you. \$\endgroup\$ Commented Aug 5, 2015 at 17:09

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