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I was looking at M851 motherboard schematic to learn something from these documents and saw an interesting circuit for microphone. look:

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1- What are the purpose of those resistors and capacitors network before the mic jack? for filtering? How do they work?

2- which one of these lines bias the capacitor microphone?

Looks like the gain of the both Op-Amp isn't so high? am I right? why? because I've worked with these kind of Microphones, you need a gain around 200 to amplify the output of the Mic.

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  • \$\begingroup\$ If you put it into a simulator, what frequency response do you get though the network? With capacitors in series for blocking DC, this should form a high pass filter. \$\endgroup\$
    – winny
    Commented Jun 30, 2016 at 9:12
  • \$\begingroup\$ @winny High pass filter? are you sure? you must be kidding me! I thought it could be several Low-pass filter! totally it's a tough circuit. \$\endgroup\$
    – Roh
    Commented Jun 30, 2016 at 9:44
  • \$\begingroup\$ R25 and C13 form a high pass filter. \$\endgroup\$
    – winny
    Commented Jun 30, 2016 at 10:33

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The only thing "conventional" about the circuit is R26 and R32 which are the 6.81K resistors as defined in IEC 61938. These are what actually applies the voltage to the audio path.

R21/R23 and R33/R36 take "VDDA" (whatever voltage that is????) and divide it in HALF to produce the (unknown) phantom voltage. C8/C16 are a local filter/bypass for the phantom voltage. C13/C14 typically isolate the phantom voltage from the "downstream" parts of the circuit. The "External Mic" jack circuit on the right is drawn "backwards" with the signal flowing into the mic jack and towards the left. Unless, of course, this is some kind of OUTPUT circuit??

The biggest mystery is R25/R31. If we removed the "phantom voltage" with the DC-blocking capacitors C13/C14, then why is it "re-inserted" with R25/R36? And what is the purpose of R27/R29? With such a low value (presumably 100Ω).

Now, it seems possible that the voltage-dividers R21/R23 and R33/R36 are creating "VDD/2" to properly bias U1A/U1B since this appears to be powered from a single-ended power source. Presumably it is battery operated and very small judging by the package sizes of the resistors and capacitors.

C12/C15 appear to be conventional RF-blocking capacitors on the vulnerable input nodes. But what is the purpose of R28/R30 which appear to be zero ohms?

I agree it is an odd circuit. Why take the (presumably limited) battery voltage (VDD) and divide it in HALF to product the "phantom voltage"? Why block the DC with C13/C14 only to re-introduce it with R25/R31?

And I agree that the gain of U1A and U1B seems remarkably low gain, apparently only 10X as set by the ratio of R20/R22 and R34/R35. Unless the circuit feeds into whatever internal mic preamp is already there (not revealed in this fragment of the schematic diagram).

It would be rather helpful to know what kind of gadget this is. It might help understand some of the seeming odd circuit design choices.

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    \$\begingroup\$ Are they biasing it to half the Vcc voltage to feed an single supply op-amp and ADC downstream? \$\endgroup\$
    – winny
    Commented Jun 30, 2016 at 10:34
  • \$\begingroup\$ Right. That is why I mentioned creating "VDD/2" in the fourth paragraph. \$\endgroup\$ Commented Jun 30, 2016 at 16:41
  • \$\begingroup\$ Good, then we are on the same page. The overall circuit looks quite overengineered compared to your run of the mill jack input with just DC deblocking, pull up to half Vdd and possibly a high pass to anti-alias the DAC. \$\endgroup\$
    – winny
    Commented Jun 30, 2016 at 19:42
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Firstly, this shows a circuit being part of a computer main board. Here you connect a consumer level microphone to the computer. These generally expect a few volts of current. This is very different from the 48V phantom power used for professional mics.

Here VDDA is probably 5 to 10 V. This is first halved and then fed to the two mic channels, left and right in order for the mic to powered if it needs it.

R25/R31 biases the signal at half supply voltage in order for the op-amp to work. The opamp is fed from the same VDDA.

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