Solving 5 variables Karnaugh map - grouping with hazard

Question

Welcome, according to topic Solving 5 variables Karnaugh map - grouping I would like to ask you if for this exercise, should I create anti-hazard group? Is it good?

The solver http://www.32x8.com/ which was mentioned does not show anti-hazard groups, so I am not sure if my thinking is good.

Usually, no. If there are specific circumstances why a hazard may be a problem, yes. One example of the latter may be using teh output of asynchronous logic as a clock signal. — user16324, Commented Aug 3, 2016 at 13:11
When minimizing a Boolean equation you dont include the anti-hazard groups since when they are included the Boolean eqn. still can be minimized, you should only include them if you really need them [if you worry about Glitches or you want to build a Lenient device] — Elbehery, Commented Aug 3, 2016 at 18:46

Jakub Rakus · Accepted Answer · 2016-08-03 20:30:39Z

-1

In the above sum there is no need to consider the red one as the four 1's are already mapped by blue and green group. So the answer will be:

$$F = C{\overline D}{\overline E}+{\overline A}B{\overline C}E+{\overline A}BD{\overline E}$$

Jakub Rakus

2,2355 gold badges19 silver badges26 bronze badges

answered Aug 3, 2016 at 17:26

VRSP SRIRAJ

11 bronze badge

Add a comment |

1 Answer 1