We need to find the power delivered by the 5V source in the above network. I usually apply superposition theorem when I need to find the power delivered by a source when there are many power sources in the same circuit. But here I am not able to understand how to approach.
2 Answers
First, calculate the current through the 3 Ω
and 2 Ω
resistors by simple Ohm's law (I = V⁄R
). The result is shown in the following figure (they are denoted by I1
and I2
).
Next task is to calculate the current through the 5V
source which is denoted by I3
. We can use Kirchoff's Current Law (KCL) either at Network 1 or Network 2.
Lets say we apply KCL at Network 1. Here, we can write -
I2 + I3 = I1
Or,
I3 = I1 - I2
Or,
I3 = 2A - 1A = 1A
So, we have found the value of current through the voltage source is 1A
. So, the supplied power by the voltage source is 5 × 1 = 5W
.
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\$\begingroup\$ Wow, that's a much simple method. \$\endgroup\$ Commented Nov 28, 2018 at 11:10
Since you know the voltage across each resistor, you can find the current through it.
Knowing that, you can use the cut-set form of KCL to find the current through the 5 V source.
Knowing the voltage and current through the source, you can find the power it delivers to (or absorbs from) the rest of the circuit.
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\$\begingroup\$ Oh. Thanks. So I need to use knowledge of Graph Theory here. Ok. \$\endgroup\$ Commented Nov 27, 2018 at 22:50
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\$\begingroup\$ Most of the graph theory is only needed if you want to program a computer to find the necessary cut sets to fully analyze a circuit. To solve this problem you just need to know that if you draw a line that divides the circuit in two, the algebraic sum of currents across that line must be zero. More detail in an old answer of mine. \$\endgroup\$ Commented Nov 27, 2018 at 22:55
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\$\begingroup\$ Ok. Thanks again. Is Deoser Kuh a good book for Circuit Analysis? Or I should use Hayt Kemmerly? \$\endgroup\$ Commented Nov 27, 2018 at 23:21
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\$\begingroup\$ Chua, Desoer & Kuh is the one I learned from, but that was a long time ago. \$\endgroup\$ Commented Nov 27, 2018 at 23:43
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\$\begingroup\$ I also read some chapters from it and I think now also its worth reading. \$\endgroup\$ Commented Nov 28, 2018 at 0:11