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I've been looking at the following article: https://www.electronics-tutorials.ws/combination/comb_2.html

I am confused as to how the boolean expression Q = a'b'A + ab'B + a'bC + abD is deduced for mux4, and what it would be for mux2. How is it done with kmaps?

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  • \$\begingroup\$ Please post all of the information needed to answer the question in the question body. \$\endgroup\$
    – Eugene Sh.
    Commented Sep 26, 2019 at 14:50

1 Answer 1

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It's pretty intuitive, actually. Based on the states of a and b, one of the 4 terms of a'b'A + ab'B + a'bC + abD will have a chance of being true. If ab=00, only the first term can be true, and only if A is true. If ab=01, then the output is true iff B is true, and so on.

The 2-mux would be a'A + aB.

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