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I have this scheme. enter image description here

I have all the parameters: L1=110 uH

C1=160 nF

C2=5 nF

Rt=1.2 kΩ

ω1=45290 rad/s

ω2=162089 rad/s

ω3=238366 rad/s

ω4=276982 rad/s

But I dont understand how to calculate the voltage source. I have this formula for it: enter image description here So my job is to calculate \$ i_{2}^1 \$ in harmonic \$w_{1}\$, \$ i_{2}^2 \$ in harmonic \$w_{2}\$, \$ i_{2}^3 \$ in harmonic \$w_{3}\$, \$ i_{2}^4 \$ in harmonic \$w_{4}\$.

QUESTION: I don't get how to calculate this voltage source. I'm not sure how to replace sin(wt), what's the the time(t)?

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  • \$\begingroup\$ Smells of XY - ultimately what are you trying to achieve with this question? \$\endgroup\$
    – Andy aka
    Commented May 12, 2020 at 13:42
  • \$\begingroup\$ What is XY? I'm trying to solve my problem for university. \$\endgroup\$
    – Simeon Simeonov
    Commented May 12, 2020 at 13:44
  • \$\begingroup\$ XY problem \$\endgroup\$
    – Andy aka
    Commented May 12, 2020 at 15:32
  • \$\begingroup\$ Seems like it's not. I added all the info just to not waste time for any further questions, if it somehow happens. \$\endgroup\$
    – Simeon Simeonov
    Commented May 12, 2020 at 15:59
  • \$\begingroup\$ Do you want to know what \$sin(\omega_n\cdot t)\$ means? \$\omega_{1-5}\$ are not harmonics BTW. \$i_2^4\$ reads as the 4th power of \$i_2\$ - is that actually what you mean? \$\endgroup\$
    – Andy aka
    Commented May 12, 2020 at 16:05

1 Answer 1

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Use superposition and calculate each component of i2 individually. Each of the different frequency components of the source will be 5@0 degrees.

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