2
\$\begingroup\$

Clarification:

I appreciate everyone's input so far. The alternatives suggested are interesting, but for this application none of them seem better than the one presented here (except possibly switching M1 with a pnp). What I'm really looking for here is pitfalls with this circuit, rather than alternatives (for example, testing oscillation, input transients, output transients).

End clarification

I'm working on a relatively low power system (10's-100's of mW) that needs to operate from around 1.5V to 12V input. The current system can operate between 1.1V to 5V, but voltages higher than that will damage it. To be clear, it will use up to 100's of mW at both 1.1V and 5V. I've been having trouble finding an LDO thats small and also can handle such low input voltages, so I was wondering what the pitfalls were of just making a discrete one as shown below. The accuracy of the output regulation is unimportant, as long as it doesn't reach 5V. Assume the power dissipation of the mosfet is unimportant for now. It seems to work pretty well in spice. Currently I'm focusing on the DMP1081UCB4 datasheet here.

schematic

simulate this circuit – Schematic created using CircuitLab

There is some oscillation caused by the added base capacitance (5n at the moment), but this is probably acceptable for this application (although removing it would be good). The overshoot is also ok.

enter image description here

Green is the voltage output, blue going high represents the load switching from 3mA to 300mA, at 12Vin (which switches on at 1ms).

enter image description here

This is the same situation, except going from 0.3mA to 170mA (which is a more reasonable approximation of the load).

\$\endgroup\$
1
  • \$\begingroup\$ Comments are not for extended discussion; this conversation has been moved to chat. \$\endgroup\$
    – Voltage Spike
    Commented Jun 13, 2020 at 4:24

3 Answers 3

1
\$\begingroup\$

The pfet/pnp acting in common emitter mode has a high impedance node which acts with the regulator's load at low load currents (high impedance load) to create an additional low frequency pole which has the potential to cause instability. A capacitor which has an ESR within a particular range is added across the output to add a zero to the loop which cancels out the extra low frequency pole and creates stability. with low impedance loads (high load currents) the extra pole moves up in frequency and makes the regulator more stable.

\$\endgroup\$
3
  • \$\begingroup\$ Could you explain this a bit more? What sort of range of ESR do you mean, for example? What would instability look like (more severe oscillation?) \$\endgroup\$
    – BeB00
    Commented May 17, 2020 at 8:14
  • \$\begingroup\$ Have a look at "analogue devices AN-1099 Application note" where they specify an ESR <1 Ohm to ensure stability. Sometimes a minimum is also specified. If the ESR of the capacitor doesn't fall within the specified range then continual output oscillation can occur. analog.com/en/analog-dialogue/articles/… \$\endgroup\$
    – user173271
    Commented May 17, 2020 at 9:13
  • \$\begingroup\$ @BeB00 mikrocontroller.net/attachment/62590/LDO_Oscillosation.pdf \$\endgroup\$
    – user173271
    Commented May 17, 2020 at 9:40
1
\$\begingroup\$

The circuit below was developed by me in about 2001.
I have used thousands of the FET based version of the circuit.
The circuit shown is a subset of the final design as current limiting was added but as-is it will work well.
It will be seen that the circuit is close to identical to your one.

See the long discussions in the links I provided.
It has no significant problems.
It can be used as a switcher or as a linear version.
The pass transistor passes voltage through with minimal drop (Vsat for bipolar, Rdson series R for FET version), and transitions smoothly with no drama into switching mode or linear regulation when Vin > Vreg.

Information in the references cited below may be of assistance. I'll not repeat the content here except to show that the circuitry is essentially identical to yours - with an important and optional difference (add an inductor and you get a smps) - leave the inductor out and it's a linear regulator.

Have a look at both the circuits in "4. Even Cheaper" in my 2015 SE Answer here
Peer Review of Buck Converter - you'll find the circuits extremely familiar!

Bipolar only. Remove D1 & L1 and it is functionally identical to your circuit - and works accordingly. Add the diode and inductor to your circuit and it's 'a switcher'.
The added gate drive resistor and zener in my FET based version allows very high input voltage in my application (from below Vreg - where it acts as a pass through - to in excess of 200V).

For either version shown below transition from pass through to switching is very smooth - making it ideal for your application. Below Vregulated the circuit acts as a linear pass through with minimal voltage drop. Above Vregulated switching action starts.

enter image description here

Bipolar driving FET.
Same comments re inductor and diode apply.
Look familiar ? :-)

enter image description here

Also, the 2004 discussion of the 2nd circuit there in this extensive discussion of "my" God's switching regulator*

If after reading that reference (long :-) ) you want to know why I called it by that name feel free to ask offlist :-).

\$\endgroup\$
6
  • \$\begingroup\$ I'm not really looking for a switching converter for this (for various reasons). If you remove the switching part, the circuits are pretty much identical, but I'm trying to find out what the pitfalls are of the circuit. \$\endgroup\$
    – BeB00
    Commented May 17, 2020 at 22:56
  • \$\begingroup\$ @BeB00 I have used thousands of the FER based version of the circuit. The circuit shown is a subset of the final design as current limiting was added but as-is it will work well. See the long discussions in the links I provided. It has no significant problems. It can be used as a switcher or as a linear version. The switcher passes voltage through with minimal drop (Vsat for bipolar, Rdson series R for FET version, and transitions smoothly with no drama into switching mode or linear regulation when Vin > Vrg. \$\endgroup\$
    – Russell McMahon
    Commented May 18, 2020 at 9:46
  • 1
    \$\begingroup\$ so for example, one issue that I'm seeing in simulation of my circuit is overshoot. Fast transients on the input cause the output to rise out of regulation, for various reasons including the gate capacitance of the mosfet. I simulated your exact circuit (without the inductor) and it has the same problem, with the voltage rising to >28V for over 1ms when the input steps from 0V to 100V. Have you tried simulating this? I searched through all the discussions for the terms "overshoot", "transient", and "step", and didn't find anything \$\endgroup\$
    – BeB00
    Commented May 18, 2020 at 10:39
  • 1
    \$\begingroup\$ @BeB00 When I built the circuit I used no simulation. I built the circuit, initially probably on breadboard or vero board (vector board) - I'd have used a psu input to start and an exercise machine alternator next (as that's what it was for). . || What Vin risetime? You'd need to look at realistic V100 rise times (mine was up to 200V in)(or more) . Cbuk2 affects response time. || Mine drove various logic circuits - some with regulator. 28V would have destroyed things. | I've not used the cct for a while. My recollection is that the real world results are very benign. ... \$\endgroup\$
    – Russell McMahon
    Commented May 19, 2020 at 11:30
  • 1
    \$\begingroup\$ In your case a 4v7 or 5V6 or ... zener on the output would help with Vout set to somewhat below zener voltage. \$\endgroup\$
    – Russell McMahon
    Commented May 19, 2020 at 11:30
1
\$\begingroup\$

Use a depletion mode FET to limit the voltage available,

schematic

simulate this circuit – Schematic created using CircuitLab

When the FET's threshold voltage is reached it will pinch off output giving a crude form of voltage regulation.

schematic

simulate this circuit

This arrangement seem to limit at about 2.4V with only a small fraction of a volt drop-out.

if you need a little more voltage you can jack he base up a bit.

schematic

simulate this circuit

source regulation is pretty good. load regulation is so-so, so put a big capacitor on the output side to reduce ripple caused by load changes.

\$\endgroup\$
2
  • \$\begingroup\$ This is definitely an interesting concept, it looks like the variety of depletion mode fets is pretty low, but I'll definitely look at them to see if that would work for me. Initially it looks like the resistance might be too high (a lot of them are in the ohms range at 0Vgs, for example, which will only get worse as the input voltage goes up) \$\endgroup\$
    – BeB00
    Commented May 17, 2020 at 8:12
  • 1
    \$\begingroup\$ you can parallel several, or jack the gate up with a zener and capacitor (and a resistor) if you need more current or more voltage \$\endgroup\$ Commented May 17, 2020 at 8:55

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.