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I am attempting to install auxiliary reverse lights in my vehicle and have come to the end of my useful knowledge.

I am confident I could simply install new LED's splicing a relay into the existing Reverse wires, but id also like to install an additional relay with a switch to operate lights manually.

If I wire the feed wires from both relays to the same light should I put a diode in both positive wires to prevent back feeding each other?

I've made a quick diagram of how I think it would look.

Would this even be the best way to achieve what I'm attempting?

enter image description here

enter image description here

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  • \$\begingroup\$ I should have mentioned, I already have a harness that I’m attempting to incorporate. I’ve added a picture with everything in it. Also as you’ll see the harness has + and -, so I figure instead of grounding to the frame or body I will just wire “ground” to what I understand is the - of my harness. \$\endgroup\$ Commented Jun 10 at 22:05
  • \$\begingroup\$ Existing reverse bulbs are 16Watts each side. LEDs are 18 watts each side. Hopefully that helps. \$\endgroup\$ Commented Jun 10 at 23:26

2 Answers 2

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You can do this with one additional relay:

schematic

simulate this circuit – Schematic created using CircuitLab

You would include optional diode, D1, if you don't want the existing lights to come on when you manually activate you new lights.

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  • \$\begingroup\$ If the aux light is low-power, you could even forego the relay entirely and drive it directly through 2 diodes. \$\endgroup\$
    – marcelm
    Commented Jun 10 at 20:47
  • \$\begingroup\$ @marcelm I thought about that too. But no load or capacity requirements/specs were provided. But in that case you can do with at most 1 diode; the additional switch wouldn't need a diode. \$\endgroup\$
    – MOSFET
    Commented Jun 10 at 20:57
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    \$\begingroup\$ That's true, and I agree it doesn't have to be part of your answer. But I thought I'd leave a comment for any readers :) - "The additional switch wouldn't need a diode" - Also true, but that would result in a different brightness of the aux light depending on which source drives it. Which may be fine, or it may be undesirable. \$\endgroup\$
    – marcelm
    Commented Jun 10 at 21:02
  • \$\begingroup\$ Forgive my lack of understanding, but I don't understand the circuit going from 85 which is ground/negative back to the Trigger voltage from the ECU/existing Circuit. \$\endgroup\$ Commented Jun 11 at 14:12
  • \$\begingroup\$ @Wire_licker That's chassis ground. It's implied the the frame ground of the vehicle is common (Battery negative). \$\endgroup\$
    – MOSFET
    Commented Jun 11 at 14:50
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It depends on what kind of relay you are using. For a standard automotive relay (such as Bosch) you can do it with a single SPDT relay.

In the diagram, when the brake lights are on the relay will close and the LED will be powered from Switched +12V through the normally open contact (87). When the brake lights are off the LED is connected to the manual switch through the normally closed contact (87A).

So when the manual switch is closed the LED will light with the brakes either off or on.

You have to be mindful of the relay coil contacts, some have a built in diode so are polarity sensitive, typically you put the positive of the trigger voltage to 86.

Here's a diagram of a relay with a diode, not that positive should go to 86, negative to 85.

relay with diode

Some relays have a resistor instead of a diode, some don't have either, these types are not polarity sensitive but it's best to follow the polarity convention in case someone comes along later and replaces it with one that does have a diode.

Note that this circuit will only activate the LED with the manual switch. If you want to activate the existing brake lights as well it depends on how the brake lights work, if they have one side grounded and the other side switched hot you can use the circuit from MOSFET's answer, if they're ground side switched it's more complicated.

schematic

simulate this circuit – Schematic created using CircuitLab

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  • \$\begingroup\$ Forgive me, I am very new to all this. In your diagram are the two brake lamp hi/lo both positive? My understanding is 85 would be Ground/negative of my harness. \$\endgroup\$ Commented Jun 11 at 14:22
  • \$\begingroup\$ @Wire_licker No, Brake Lamp Hi would be the positive, Lo would be the negative which typically would be ground but on some vehicles it might not be. If your brake lights have one side grounded that side would go to 85. For a relay without a built in diode you can hook 85 and 86 up either way, but the ones with a diode need to be hooked up 86 positive, 85 negative. \$\endgroup\$
    – GodJihyo
    Commented Jun 11 at 14:51

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