I have an Aglient power supply Model number N5747A, and I want to use its current sinking ability to become an active load.
This is to test a DC/DC converter (5VDC Output), Gaia MGDS-35-H-C, I want to load the output of the DC/DC to 75% load.
Requirement of Electronic Load I am using an active load because I need to vary the load from 1% to 100% in 15 steps. An active load will be smoother and more accurate.
According to the datasheet 75% load is around 5.25A. My idea is to hook up the Agilent power supply and set the current limit to 5.25A on the output of the DC/DC converter.
My question is, what kind of "fixed" resistance would I need, would it be just to protect the Agilent supply and DC/DC converter? I assume I would need some kind of power resistor.
The power supply will create a current loop and force the DC/DC converter to draw 75% of its maximum current. Am I correct in my understanding of this?
Below is a drawing for 100% load (7A) on the output of the DC/DC converter
Then the fixed resistance I chose was to maintain a safe operating voltage for the current sink. Example: 60V current source, to maintain 7A's of current through the loop a 4 Ohm resistor will operate the current source in the middle of its operating voltage range of around (28V - 5V )= 23V. If you chose an 8 Ohm resistor for example, then you'll be operating really close to the supply's limits (7A * 8 Ohms = 56V-5=51V). Also the fixed resistor limit in cause the supply goes to 0V (a dead short), so at least 5V/7A = 1 Ohm minimum (rounded up for safety) to put a fixed cap on the current that will flow.