I am very new to calculating frequencies, but here goes...
The datasheet for an infrared LED states that it can handle a current of up to 1A when the voltage is pulsed at 300 pulses per second and a pulse width of 10us:
Am I correct in thinking that this equates to a frequency of 300Hz with a 0.3% duty cycle? I get the frequency by:
1 second/300 = 0.0033 second = 300Hz
and I get the duty cycle by dividing "on time" by period, if 10 us = 0.00001 seconds
(0.00001 seconds / 0.0033 seconds) = 0.003 = 0.3%.
So then my other question comes when I read this article on Wikipedia that states that many electronics pulse IR at 38 kHz:
And there's a tutorial I read that instructed me to pulse the voltage at about 13 seconds on and 13 seconds off for 38kHz. Isn't that a 50% duty cycle? How can the duty cycle be so much bigger when the pulse "on time" is nearly the same? Is it assuming a much smaller current than 1A?