4
\$\begingroup\$

I have a device that is powered by a coin cell battery, but occasionally they fail and I would like to run them in debug mode to find the problem. Debug mode requires more power than the coin cell can produce. Sometime I want to flash new program code on them which also requires too much power for the coin cell to handle. My batteries are soldered on; it is inconvenient to remove the battery.

Is it safe to hook up a power supply in parallel to my coin cell? If the coin cell is at 2.9V, can the power supply be at 3.1V? What are the considerations for this configurations? Does anyone have a application note or paper that covers coin cells?

I don't want to put a diode in front of my battery because that causes a constant 0.7V drop.

\$\endgroup\$
1
  • \$\begingroup\$ Can't you just modify one of them as a "debug rig"? \$\endgroup\$
    – PlasmaHH
    Commented Nov 21, 2014 at 22:37

1 Answer 1

7
\$\begingroup\$

If you regulate the supply to 3.0V then it should be OK. A coin cell that is nearly flat will get charged slightly (until its voltage rises to match the supply) but that shouldn't hurt it. Voltages higher than 3.0V might damage the cell. If you can't hold the voltage down to 3.0V then you will need some way to isolate the battery. Here are a few ideas:-

  1. Put a high current Schottky diode in series with the coin cell, which should drop less than 0.2V at low current.

  2. Install a jumper or switch to disconnect the battery when using external power. If the voltage difference is small then it should be OK to leave the battery connected for a few seconds during the transition, otherwise you could include a large capacitor to hold the voltage up between switching the battery out and applying external power.

  3. Disconnect the cell automatically using a power jack which has a built-in battery disconnect switch.

  4. Use a FET to switch the coin cell in when external power is not present. Unlike a diode this has minimal voltage drop when on battery power.

enter image description here

\$\endgroup\$
1
  • \$\begingroup\$ well explained options! \$\endgroup\$ Commented Feb 17, 2017 at 7:48

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.