0
\$\begingroup\$

The main goal is to make our current speaker louder. The second goal is to use a speaker with a smaller form factor than our current horn that is louder.

We are using a 24Vp-p DC circuit (push +12V / pull -12V off of a 12V source) that we are using PWM to send different frequencies to an 8 ohm Horn. According to the horn datasheet it is designed to use a 24Vp-p square wave. http://www.promover.com.tw/en/main_index.php?menu=product_inside_item&p_id=541

The signal looks like this. 24Vp-p

If I put a 33uF capacitor in series with the horn then it looks like the image below. The image below shows a horn circuit signal with no capacitor and a horn circuit signal with a capacitor stacked on top of each other. The 33uF capacitor helps block the DC which I think is a good thing, but it is quieter and that is not what we are going for. According to this website http://education.lenardaudio.com/en/07_horns_2.html they recommend using a 47uF capacitor for 800 Hz to 8KHz Are there any cases where filtering the signal can make it louder? I am only familiar with filtering a signals that are outside of the bounds of a speaker frequency response. I do not know of any ways to change a circuit to make a horn louder. no cap and 33uF

Is there anything that I can do to make a single horn louder for this circuit?

We looked into an 8 ohm speaker as we are looking into a smaller profile http://www.visaton.com/en/industrie/breitband/fr10_8.html and it was not as loud as the horn even though it has a better frequency response and higher wattage ratings. However, while doing some research it appears that horns are very efficient at being loud, and speakers need to have a properly sized / ported cabinet in order to achieve maximum loudness.

According to the internet a 4 ohm speaker is not louder than an 8 ohm speaker due to the amplifier has trouble sourcing enough current for a 4 ohm speaker for the same loudness as an 8 ohm speaker. However, wouldn't a 4 ohm speaker be louder in my case assuming that the PCB and wires are capable of handling the extra current and my 12V rails stay at 12V?

The frequencies that we are interested in are 100 Hz to 2.5 KHz. Our horn is used for playing solid tones and different buzzer / car alarm sounds and audio clarity is not of too large of a concern as it will not be playing back music or voice audio.

So to summarize, my three questions are.

  1. Is there anything I can do in my circuit in order to make the horn louder other than using a higher voltage which is not an option?
  2. Is there a better type of horn or speaker that uses a thinner profile than our current horn, but is louder and has a better frequency response (100 to 2.5 kHz)?
  3. Will going to a 4 ohm speaker be louder than an 8 ohm speaker in this case?
\$\endgroup\$
  • \$\begingroup\$ Without a schematic to refer to, we are helpless. \$\endgroup\$ – WhatRoughBeast Jun 3 '16 at 20:49
  • \$\begingroup\$ Use an amplifier with a 4 ohm driver. \$\endgroup\$ – Passerby Jun 3 '16 at 21:02
  • \$\begingroup\$ The schematic is irrelevant since I have shown the output for the audio signal. Is there something that I can do (IC, Filter, circuit) with that audio signal on my pcb to make the signal louder? \$\endgroup\$ – tooclosetosee Jun 4 '16 at 3:08
  • \$\begingroup\$ @Passerby Are you referring to using a separate off board amplifier, or an amplifier IC or circuit that I can use on my PCB? \$\endgroup\$ – tooclosetosee Jun 4 '16 at 3:09
1
\$\begingroup\$

Is there anything I can do in my circuit in order to make the horn louder other than using a higher voltage which is not an option?

No, there isn't. With a 24 volt peak-to-peak square wave into the voice coil, that's the same as feeding 12 volts DC into a 6 ohm resistor, which means that - under those conditions - the power your voice coil is dissipating is 24 watts.

Also, there's a problem with the data sheet, since that 1 ampere current limit translates to 12 watts, not their specified 20 watts max.

enter image description here

Will going to a 4 ohm speaker be louder than an 8 ohm speaker in this case?

Maybe, maybe not. The speaker's impedance doesn't determine how loud it is, what matters, basically, is the geometry of the horn, how far the diaphragm can flex, and how much current you can put into the voice coil before it melts.

| improve this answer | |
\$\endgroup\$
0
\$\begingroup\$

You may be out of luck at the lower frequencies. Your problem is probably not electronics but more acoustics.

The horn is meant to run at frequencies above 1000 hz. At lower frequencies, volume can only be obtained by a combination of larger area and greater displacement of the moving members. You simply don't have enough geometry to get a response.

If you look at the chart on the data sheet, you will see that the output is about 70 dB at the low frequency and 100 dB at high frequency. (Now I am going to show my age.) A "Bel" is simply a factor of 10 (courtesy Bell Tel. Co.) and 30 deciBels = 3 Bels so the difference between low and high frequencies is three factors of ten, or 1,000. So if you want to use this horn, you need to be 1-4 kHz and best 2500 Hz.enter image description here

| improve this answer | |
\$\endgroup\$
  • \$\begingroup\$ Are you familiar with a horn that is best in the 100 Hz - 2 kHz range? From what I understand, horns are more efficient and are better than speakers for making loud noises. However, like the one that we have, the frequency response is 1 kHz and up. Here is a link that seems very helpful, but shows just a speaker for 100 Hz to 2.5 kHz that we are interested in. \$\endgroup\$ – tooclosetosee Jun 4 '16 at 3:18
  • \$\begingroup\$ Unfortunately, you need more surface area than a sounder horn provides to get to low frequencies. This is why the low frequency parts for audio systems are larger, and why tubas are so big. On the other hand a flute or fife can produce a piercing sound despite its small size at higher frequencies. At this frequency band your sounder will most likely be more of a speaker than a horn. \$\endgroup\$ – John Birckhead Jun 4 '16 at 15:38

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.