I need to measure inductors with a small DC bias current. Small is a relative term and here as in won't cause any significant voltage drop in the cables of the LCR meter but enough to put my inductor near saturation. There are a few high end production test models which has this built in but it's way above my price range. The ones which has DC bias are always rated in voltage only which makes perfect sense for a capacitor measurement but assuming my DC source does the constant current limitation, am I missing something? 10 V maximum, sure, but how much current can I pass though it? Will the L-measurement DC-block the DC voltage imposed by my external current over the resistance in the wire of the coil (DUT)?

Here is one example: datasheet

  • \$\begingroup\$ Why do you need to have a small DC bias current flowing to do the measurement. As far as I know the value of an inductor does not change (significantly) for small DC currents. At the saturation current of course it does but not for small currents. \$\endgroup\$ – Bimpelrekkie Jul 5 '16 at 8:31
  • \$\begingroup\$ Sorry about that, I'll edit the text to make it more clear. \$\endgroup\$ – winny Jul 5 '16 at 8:37

Feed a constant current (high compliance) through the inductor and couple the input lead of the LCR meter via a 100 uF capacitor. The capacitor should decouple the measurement circuit from the DC circuit adequately and not pose much of a significant measurement error when measuring inductance.

It's easy to try.

  • \$\begingroup\$ This was my original thought, as per powerelectronics.com/site-files/powerelectronics.com/files/…, but since I need a more fancy LCR meter anyway, why not one with DC bias option I thought. This leaves me with the question, if I can't run current though the DC bias port of most LCR meters, is their purpose only to bias capacitors? \$\endgroup\$ – winny Jul 5 '16 at 11:33

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