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I'm building a small class D amplifier: some op amp circuits for pre-amplification, a pwm modulator based on a dsPIC, some power buffers for controlling the gates of an h-bridge power stage, and a LC output filter.

To power the system I bought a cheap (7€) power supply 12V, 5A. A photo below to give the idea of the device: enter image description here

I tested it and it seems quite strong: while increasing the current flow the voltage always remained at a fixed value.

The problem is that every 15us there is a very high frequency oscillation (~1MHz, ~2V amplitude) on the output. Images below:

enter image description here

To reduce the output of these pulses i tried:

  • An additional LC filter (L=200uH, C=30uF tantalum) on the output. The ripple still remains and I don't know why.
  • A 12v standard zener regulator. The ripple still remains (maybe because the frequency is too high for a zener diode???)

What else do you recommend to do?

Thanks

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    \$\begingroup\$ how are you probing your psu? maybe its radiated noise, not conducted \$\endgroup\$
    – Wesley Lee
    Commented Jul 27, 2016 at 17:40
  • \$\begingroup\$ @Wesley Lee I don't think it is radiated noise because it is not a constant sine waveform but is an oscillation that happens every 15us with a very high frequency and dies in about 500ns. It's like a high frequency heart beat. \$\endgroup\$
    – Dukenukem
    Commented Jul 27, 2016 at 18:46
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    \$\begingroup\$ radiated noise does not have to be a sine wave.. \$\endgroup\$
    – Wesley Lee
    Commented Jul 27, 2016 at 19:08
  • \$\begingroup\$ Try putting a load on the output. \$\endgroup\$
    – Andy aka
    Commented Jul 27, 2016 at 19:09
  • \$\begingroup\$ Tantalum capacitors do not work well at high frequencies. Try a ceramic instead. You don't need to be down at fc=2kHz (which may be detrimental to your audio), as you are targeting noise that is around 50MHz. \$\endgroup\$
    – Mark
    Commented Jul 27, 2016 at 20:00

1 Answer 1

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Your power supply appears to be missing the Y capacitor which will make it more difficult to measure the output noise (the 2V you are seeing is almost surely not real). It does have what look likes a nice common-mode choke and X capacitor(s).

enter image description here

The purpose of this capacitor is to conduct some of the 67kHz switching noise out to the earth terminal. It must be a safety rated capacitor designed for Y use. Don't just stick any old cap in there- this is a safety issue.

http://photos.prnewswire.com/prnvar/20130521/CL18315

To get a better measurement, try grounding the supply output to earth and using a differential measurement on the output terminals (A-B with two scope probes). Just grounding the output deliberately (not through the scope probe) should help.

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    \$\begingroup\$ Thank you @Spehro Pefhany, using an Y1, 1000pF capacitor reduced the noise to 50mVpp. Considering that this is a classD power supply, would it be usefull to use an additional LC filter (with very low cut frequency) on the output of the smps? \$\endgroup\$
    – Dukenukem
    Commented Aug 4, 2016 at 17:30
  • \$\begingroup\$ Good to hear it made a profound difference in the measured noise. You could consider adding a common mode L-C filter (google common mode choke- something like 1mH and rated for your required current or above) but the switching frequency (and the harmonics) are way above audible so a bit of noise may not have much effect on the quality of sound. \$\endgroup\$ Commented Aug 4, 2016 at 18:25
  • \$\begingroup\$ Ok but, a common mode choke is only for AC (so it should be placed in the 220V AC line), am I right? Would be useful to add an extra LC (with a simple 1-wire-inductor) filter between the output of the smps and the classD circuit? \$\endgroup\$
    – Dukenukem
    Commented Aug 5, 2016 at 16:47
  • \$\begingroup\$ You can use a common mode choke equally well on DC! \$\endgroup\$ Commented Aug 5, 2016 at 17:12
  • \$\begingroup\$ Can you please explain me why it would be better to use a common mode choke instead of a standard LC filter? I dont get exactly why someone should use one instead of the other. \$\endgroup\$
    – Dukenukem
    Commented Aug 8, 2016 at 12:51

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