P-I-N structures are an improvement from simpler PN photodiodes. You can get higher responsivity values with them since there is more area for light absorption.

But that made me think... why do you need the P and N doped semiconductors in the first place? For the built-in electric field? That can be compensated with an external bias voltage (Which is used anyway in P-I-N photodiodes).

Thanks a lot in advance.

  • 1
    \$\begingroup\$ How does a PN or PIN diode junction have a build-in electric field? There are energy band differences but that is not the same as an electric field. Intrinsic (non or lightly doped) Silicon is not a good electric conductor and therefore not a very useful material to make semiconductor components from which can conduct usable currents. \$\endgroup\$ Sep 19 '17 at 15:05
  • 1
    \$\begingroup\$ The built-in Potential and field is due to the space charge region at the electrode surface, created by doping a semiconductor , normally an insulator. Lower doping increases speed and bandwidth but degrades other factors. \$\endgroup\$ Sep 19 '17 at 15:17
  • \$\begingroup\$ With just a piece of silicon and a bias voltage you will see current all the time. And then more current with photo-excited carriers. \$\endgroup\$ Sep 19 '17 at 15:42
  • \$\begingroup\$ @Bimpelrekkie Diodes have a built in electric field caused by differences in the energy bands of the materials. That is what it is called and that is what it is. Place a positive test charge in the region and it will move in the direction of the built in field. \$\endgroup\$
    – Matt
    Sep 19 '17 at 16:24
  • \$\begingroup\$ @George Herold. And how is that different from the intrinsic material where the absorption takes place in a PIN photodiode? There is also "current all the time" due to the spontaneous e-h generation being swept away (dark current), with more current when light of the right wavelength hits the device. \$\endgroup\$
    – Frilance
    Sep 19 '17 at 17:57

Your question asks about 3 different types of light sensing devices, a photoconductor, a p-i-n photodiode, and a p-n photodiode. There are pros and cons when using each of these

This is a piece of semiconductor with ohmic contacts on the ends. When illuminated electron hole pairs are generated and, if a bias is applied to the terminals, contributes to a photocurrent in the device. The photocurrent gain of such a device can be given by:

$$G_a = \frac{(\mu_n+\mu_p)\tau\mathcal{E}}{L}$$

where \$\mu_n\$ and \$\mu_p\$ are the electron and hole mobilities. \$\tau\$ is the carrier lifetime, \$\mathcal{E}\$ is the applied electric field, and \$L\$ is the length of the photoconductor.

As you can see here, you get the best gain with long lifetimes and short photoconductors. However long lifetimes will make your device less responsive, and short photoconductors will make your device less sensitive. So there are tradeoffs.

p-n photodiode:

A p-n photodiode works basically the same way as a photoconductor, except the built in field helps to separate charge carriers. Since nearly 100% of the voltage drop occurs across the depletion region, this is the only part of the p-n photodiode that has a significant response to photons. Therefore, for a high quantum efficiency, you want a big depletion region, to capture as many photons as possible. But this increases the transit time across the depletion region, increasing the response time. So there is a trade off between quantum efficiency and response time.

Because of the built in electric field p-n photodiodes generally have faster response times than photoconductors. Carrier lifetime also doesn't matter as much in p-n photodiodes as it does in photoconductors since the recombination rate in the depletion region is so low it is usually ignored.

The dark current in a diode is generally going to be lower than in a photoconductor. This could be important when trying to detect small amounts of photons.

p-i-n photodiode: The p-i-n photodiode takes the benefits of the p-n photodiode and improves the quantum efficiency by adding an intrinsic region in the middle. This region allows you to tune the quantum efficiency and frequency response to fit your needs. Again, a negligible amount of recombination happens in the depletion region, so carrier lifetimes don't matter much.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.