In pn diode, how does an electron flow from p to n during reverse recovery phase

Question

During forward bias : An electron from the negative terminal of battery enters the conduction band of $n$ side, runs toward the junction, waits for a hole for $\tau$ seconds, when it finds one, it falls into the hole in the valence band of $p$ side, then the electron hops along the $p$ side holes and finally reaches the positive terminal of the battery.

Question1 : Why does the electron in the conduction band fall into the hole in the valence band ? Is it because the valence band has lower energy ? If so, kindly keep this in mind when looking into my second question.

During reverse bias, during recovery phase : An electron from the negative terminal of battery enters the $p$ side valence band, runs toward the junction, then what ? There are no empty energy states available in the valence band of $n$ side, so it seems the electron must climb up to the conduction band to complete the loop. ( Note that if we abruptly change from forward bias to reverse, initially, during recovery phase, there exist many diffused electrons on the $p$ side near the junction. )

Question2 : Does the electron in the valence band really climb up to the conduction band at the junction ?

Answer 1

When a PN junction is forward biased there will be excess minority electrons in the P Region due to diffusion of majority electrons in the N region into the P Region.Conversely, there well be minority holes in the N region.

When you reverse bias the PN junction the force(forward voltage) that allows for Electrons and holes to move to the P and N regions,respectively,is gone.

The question is where do these excess electrons and holes go?

Because of the electric field in the depletion region(from the N side to the P Side),excess electrons in the P side will be swept back to their original position in the N side(Electrons move in the opposite direction of the E-field).In the same Manner,holes(moving with the direction of the E-field)in the N side will be swept back To the P region.

This process causes the large reverse recovery current the moment a PN junction is Reverse biased.

As holes and electrons move back to the P and N regions,respectively,the depletion Region starts to respond the reverse voltage and widens to prevent further migration of holes and electrons and only small reverse current(leakage current) will pass Through the diode.